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3 years ago

_Nal+ _CaCl2 what's the answer ?

Chemistry

1 answer:

Sindrei [870]3 years ago

5 0

2Nal+CaCl2 should be right

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What is the term for an object's strength of motion?

Andrei [34K]

I'm pretty sure its momentum

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4 years ago

At 25°C, K = 0.090 for the following reaction. H2O(g) + Cl2O(g) equilibrium reaction arrow 2 HOCl(g) Calculate the concentration

wlad13 [49]

Answer:

[HOCl] = 0.00909 mol/liter

[H₂O] = 0.03901 mol/liter

[Cl₂O] = 0.02351 mol/liter

Explanation:

1. Chemical reaction:

$H_2O(g)+Cl_2O(g)\rightleftharpoons 2 HOCl(g)$

2. Initial concentrations:

i) 1.3 g H₂O

Number of moles = 1.3g / (18.015g/mol) = 0.07216 mol

Molarity, M = 0.07216 mol / 1.5 liter = 0.0481 mol/liter

ii) 2.2 g Cl₂O

Number of moles = 2.2 g/ (67.45 g/mol) = 0.0326 mol

Molarity = 0.0326mol / 1.5 liter = 0.0217 mol/liter

3. ICE (Initial, Change, Equilibrium) table

$H_2O(g)+Cl_2O(g)\rightleftharpoons 2 HOCl(g)$

I 0.0481 0.0326 0

C -x -x +x

E 0.0481-x 0.0326-x x

4. Equilibrium expression

$K_c=\dfrac{[HOCl]^2}{[H_2O].[Cl_2O]}$

$0.09=\dfrac{x^2}{(0.0481-x)(0.0326-x)}$

5. Solve:

$x^2=0.09(x-0.0481)(x-0.0326)\\\\0.91x^2+0.007263x-0.000141125=0$

Use the quadatic formula:

$x=\dfrac{-0.007263\pm \sqrt{(0.007263)^2-4(0.91)(-0.000141125)}}{2(0.91)}$

The positive result is x = 0.00909

Thus the concentrations are:

[HOCl] = 0.00909 mol/liter

[H₂O] = 0.0481 - 0.00909 = 0.03901 mol/liter

[Cl₂O] = 0.0326 - 0.00909 = 0.02351 mol/liter

3 0

3 years ago

Which type of fertilization and development is exhibited by birds and many reptiles?

MaRussiya [10]

Answer: Internal fertilization

Explanation: Most birds and reptiles undergoes internal fertilization in which the sperm cells are ejected and fertilizes the egg cell inside the body of the animal.

4 0

3 years ago

Use the following balanced reaction to solve 1-3:

tino4ka555 [31]

Answer:

1.96g H2

Explanation:

P4 = 123.9g/mol

H2 = 2.02g/mol

$\frac{20g P_{4} }{1}$ * $\frac{1 mol P_{4} }{123.9g}$ * $\frac{6 mol H_{2} }{1 mol P_{4} }$ * $\frac{2.02g H_{2} }{1 mol H_{2} }$ = 1.96g H2

6 0

3 years ago

Write an equation for the neutralization of h2so4 by koh

Elena L [17]

Acid + alkali ------> salt + water
2KOH + H2SO4 ------> K2SO4 + 2H2O

Hope it helped!

3 0

3 years ago