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kobusy [5.1K]
3 years ago
9

_Nal+ _CaCl2 what's the answer ?

Chemistry
1 answer:
Sindrei [870]3 years ago
5 0
2Nal+CaCl2 should be right
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A kettle takes 3 minutes to boil. Calculate what part of an hour it is.​
daser333 [38]

Answer:

1/20

Explanation:

an hour is 60 minutes and its 3 minutes of an hour therefore its 3/60 hour  or 1/20 of an hour

3 0
2 years ago
Read 2 more answers
Ketones undergo a reduction when treated with sodium borohydride, NaBH4. The product of the above reaction has the following spe
Anna71 [15]

Answer:

The product is cyclohexanol

Explanation:

Firstly,

A ketone undergo a borohydride reduction reaction to form an alcohol as below,

R-CO-R'  ⇒ R-CO(OH)-R'

  1. IR Spectrum confirms that alcohol group is existed with the peak at 3400 cm⁻¹
  2. From 1H-NMR, the product has 10 hydrogen atoms, the MS suggest that the formula is C₅H₁₀O (M = 86). With this formula, the alcohol is monosaturated. Since, the substance already underwent reduction reaction, the only way to suggest a monosaturated compound is a cyclic alcohol. So the compound is cyclopentanol.
  3. Check with other spectroscopic properties,
  • 3 signals of 13C NMR confirms the structure is symmetrical, δ 24.2, (-<u>C</u>H₂-CH₂-CH(CH₂-)-OH), δ 35.5 (-CH₂-<u>C</u>H₂-CH(CH₂-)-OH), δ 73.3 (-CH₂-CH₂-<u>C</u>H(CH₂-)-OH).
  • 1H NMR confirms,

        1.56 δ (4H, triplet) - (-C<u>H</u>₂-CH₂-CH-OH) ; triplet as coupling with 2 H,

        1.78 δ (4H, multiplet)  - (-CH₂-C<u>H</u>₂-CH-OH); multiplet as coupling with 2H of CH₂, 1 H of CH

         3.24 δ (1H, quintet); - (-CH₂-CH₂-C<u>H</u>(CH₂-)-OH), coupling with4 H of 2 group of CH₂

         3.58 δ (1H, singlet); - (-CH₂-CH₂-CH(CH₂-)-O<u>H</u>), hydrogen of alcohol group, not tend to coupling with other hydrogen

4 0
3 years ago
Between reaction of magnesium powder and lead oxide which is oxidized in the reaction and which is oxidizing agent
GuDViN [60]

Answer:

Mg is oxidized and Pb is the oxidizing agent

Explanation:

7 0
3 years ago
When 35.0 mL of 0.400 M hydrobromic acid and 35.0 mL of 0.400 M ammonia are combined, the pH of the resulting solution will be :
Kay [80]

Answer:

B. Equal to 7.

Explanation:

Hydrobromic acid is a strong acid that decreases pH and ammonia is a strong base that increases pH.

As the initial pH of water is 7,0 the addition of 35.0mL of 0.400M HBr will produce a pH less than 7,0. But, the same effect of decreasing pH is reverted for the addition of 35.0mL of 0.400M HNO3.

That means the net effect of the two addition is to have a pH:

B. Equal to 7.

I hope it helps!

3 0
3 years ago
Give two uses of compound under each of the following, in medicine and in industry​
NemiM [27]

Explanation:

#Medicine

Compounds used as medicines are most often organic compounds, which are often divided into the broad classes of small organic molecules (e.g., atorvastatin, fluticasone, clopidogrel) and "biologics" (infliximab, erythropoietin, insulin glargine),

#Industry

Polymers and plastics such as polyethylene, polypropylene, polyvinyl chloride, polyethylene terephthalate, polystyrene and polycarbonate

7 0
3 years ago
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