_Nal+ _CaCl2 what's the answer ?

Calculate the mass of water produced when 1.36 g of butane reacts with excess oxygen.

ANTONII [103]

Answer:

Mass of water produced= 1.8 g

Explanation:

Given data:

Mass of water produced = ?

Mass of butane = 1.36 g

Mass of oxygen = excess

Solution:

Chemical equation:

2C₄H₁₀ +13 O₂ → 8CO₂ + 10H₂O

Number of moles of butane:

Number of moles = mass/molar mass

Number of moles = 1.36 g/ 58.12 g/mol

Number of moles = 0.02 mol

Now we will compare the moles of butane with water.

C₄H₁₀ : H₂O

2 : 10

0.02 : 10/2×0.02 = 0.1 mol

Mass of water produced:

Mass = molar mass × molar mass

Mass = 0.1 mol × 18 g/mol

Mass = 1.8 g

6 0

3 years ago

Water is known as a polar molecule because check all that apply. the oxygen atom has a greater attraction for electrons than the

Tju [1.3M]

<span>Water is known as a polar molecule because the oxygen atom has a greater attraction for electrons than the hydrogen atom does. Oxygen is more electronegative than that of hydrogen creating a partial charges with the hydrogen and oxygen atoms. Also, the electrons of the covalent bond are not shared equally between the hydrogen and oxygen atoms making it polar.</span>

5 0

3 years ago

Why is plant able to continue to grow and develop once starch supply in the seed is gone?

horsena [70]

<span>They have chloroplasts and use light energy to make more food. I think might be wrong </span>

3 0

4 years ago

you wish to make a 0.161 m nitric acid solution from a stock solution of 3.00 m nitric acid. how much concentrated acid must you

Drupady [299]

From a stock solution of 3.00 m nitric acid, 9.391 ml of stock solution is needed to create a 0.161 m nitric acid solution, which has a total volume of 175 ml of the diluted solution.

A chemical reagent is present in vast quantities as a stock solution. It has a uniform concentration. Examples of typical stock solutions in laboratories are nitric acid and hydrochloric acid. These play a critical role in creating the titration-related solution preparations.

We know the formula for dilution type problems

M1 VI = M2 V 2

Where,

M, = initial molarity

V , = initial Volume

M2 = final molarity

V 2 = final Volume

Hene given -

M, = 3.00 M

VI = ?

M2 = 0.161M

V 2 = 175 ml

Accordingly ' MI V1 = M2 V 2

V1 = $(M2*V2)/M1$

V1= (0.161M*175ml)/ 3.00M

v1 = 9.391

The required volume of Stock solution is 9.391ml.

Learn more about Stock solution here

brainly.com/question/25256765

#SPJ4

7 0

1 year ago

How much heat is released as the temperature of 465 g of water drops from 75.0°C to 18.2°C?

Aleks [24]

The heat released : -110560.632 J

<h3>Further explanation</h3>

Heat can be calculated using the formula:

Q = mc∆T

Q = heat, J

m = mass, g

c = specific heat, joules / g ° C

∆T = temperature difference, ° C / K

<h3>Known</h3>

m =465 g

c water = 4.186 J/gram °C

∆T = temperature difference = 18.2 - 75 = - 56.8 °C

Then the heat :

$\tt Q=m.c.\Delta T\\\\Q=465\times 4.186\times -56.8\\\\Q=\boxed{\bold{-110560.632~J}}\rightarrow -=exothermic$

3 0

3 years ago