Answer:
3.79 g of N2.
Explanation:
We'll begin by writing the balanced equation for the reaction.
This is given below:
4NH3 + 3O2 → 2N2 + 6H2O
Next, we shall determine the mass of O2 that reacted and the mass of N2 produced from the balanced equation.
This is illustrated below:
Molar mass of O2 = 16x2 = 32 g/mol
Mass of O2 from the balanced equation = 3 x 32 = 96 g
Molar mass of N2 = 2x14 = 28 g/mol
Mass of N2 from the balanced equation = 2 x 28 = 56 g
Summary:
From the balanced equation above,
96 g of O2 reacted to produce 56 g of N2.
Finally, we shall determine the mass of N2 produced by reacting 6.50 g of O2.
This can be obtained as follow:
From the balanced equation above,
96 g of O2 reacted to produce 56 g of N2.
Therefore, 6.50 g of O2 will react to produce = (6.50 x 56)/96 = 3.79 g of N2.
Therefore, 3.79 g of N2 were obtained from the reaction..
