Answer:
components of a nucleotide - DNA and RNA
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Answer:
7.12 × 10⁻³ M/s
Explanation:
Step 1: Write the balanced reaction
2 SO₂ + O₂ ⇒ 2 SO₃
Step 2: Establish the appropriate molar ratio
According to the balanced equation, the molar ratio of O₂ to SO₃ is 1:2.
Step 3: Calculate the rate of formation of SO₃
The rate of loss of O₂ is 3.56 × 10⁻³ mol O₂/L.s. The rate of formation of SO₃ is:
3.56 × 10⁻³ mol O₂/L.s. × 2 mol SO₃/1 mol O₂ = 7.12 × 10⁻³ mol SO₃/L.s
The conc of NaOH is 0.104M which means that 1000mL solution contains 0.104mol of NaOH, so the amount of moles used in the titration will be

The reaction of NaOH and HCl is one to one so the moles of HCl that were titrated will also be

The Molarity is therefore