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almond37 [142]
3 years ago
6

Over 100 existing elements are listed and classified on the ____________________.

Chemistry
2 answers:
Dmitriy789 [7]3 years ago
8 0
Periodic table.

There is every element listed on the periodic table grouped and listed properly.

Hope this helps, let me know if you have questions. Have a great day!
Nadusha1986 [10]3 years ago
3 0
The answer is Periodic table
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La masa de una olla es de 300g y contiene 90% de aluminio. Hallar el número de moles de aluminio de la olla. P.A.(Al= 27)
Neko [114]

Explanation:

The mass of a pot is 300g and contains 90% aluminum. Find the number of moles of aluminum in the pot. P.A. (Al = 27)

The mass of aluminum present in the pot is:

300 g * 90/100\\=270 g

Hence, in the given pot 270g Al is present.

Number of moles of Al=\frac{given mass ofAl}{its molar mass}

The gram atomic mass of Al -27 g/mol

Given the mass of Al is 270 g

Substitute these values in the above formula:

Number of moles of Al=\frac{given mass ofAl}{its molar mass}\\=\frac{270 g}{27 g} \\=10.0 mol

Answer is 10.0 mol of Al is present.

6 0
3 years ago
Which statement is true about this equation?
lara [203]
The appropriate response is the fourth one. The announcement is valid about this condition beneath is in spite of the fact that it is unequal, it can be adjusted by specifically utilizing observer particles.

I hope the answer will help you. 

3 0
3 years ago
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What happens when an island volcano erupts and molten lava flows out?
qwelly [4]
It will explode together cause danger  
3 0
3 years ago
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David went shopping with his mom for house renovations supplies. They were looking for materials that would conduct electricity.
maxonik [38]

Answer:

this will copper this is correct answer

7 0
2 years ago
method to measure soluble organic carbon in seawater includes oxidation of the organic materials to CO2 with K2S2O8, followed by
dusya [7]

Answer:

The ppm carbon in the seawater is 104.01.

Explanation:

Mass of seawater = 6.234 g

Mass of carbon dioxide gas  produced = 2.378 mg = 0.002378 g

1 mg = 0.001 g

Moles of carbon dioxide gas = \frac{0.002378 g}{44.009 g/mol}=5.4034\times 10^{-5} mol

1 mol of carbon dioxde gas has 1 mole pf carbon atoms,then 5.4034\times 10^{-5} mol will have ;

1\times 5.4034\times 10^{-5} mol=5.4034\times 10^{-5} mol of carbon

Mass of 5.4034\times 10^{-5} mol of carbon ;

12 g/mol\times 5.4034\times 10^{-5} mol=0.0006484 g

To calculate the ppm of oxygen in sea water, we use the equation:

\text{ppm}=\frac{\text{Mass of solute}}{\text{Mass of solution}}\times 10^6

(Both the masses are in grams)

=\frac{0.0006484 g}{ 6.234 g}\times 10^6=104.01 ppm

The ppm carbon in the seawater is 104.01.

7 0
3 years ago
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