The given statement is true .
<h3>What is Rutherford’s gold foil experiment?</h3>
- A piece of gold foil was hit with alpha particles, which have a favorable charge. Most alpha particles went right around. This showed that the gold particles were mostly space.
- The Rutherford gold leaf investigation supposed that most (99%) of all the mass of an atom is in the middle of the atom, that the nucleus is very small (105 times small than the length of the atom) and that is positively captured.
- For the distribution experiment, Rutherford enjoyed a metal sheet that could be as thin as practicable. Gold is the most malleable of all known metals. It can easily be converted into very thin sheets. Hence, Rutherford established a gold foil for his alpha-ray scattering experimentation.
To learn more about Rutherford’s gold foil experiment, refer to:
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Answer:
The answer will be approximately 1.0L
Explanation:
The problem has not been properly specified. You could have specified a gas in a PISTON, whose volume would decrease with increased pressure, and increase with increased temperature.
For such a system, we would use the
combined gas law:
=
=
=
1.0L
Phosphoric acid is a polyprotic acid. Write balanced chemical equations for the sequence of reactions that phosphoric acid can undergo when it's dissolved in water is given below
Explanation:
Many acids contain two or more ionizable hydrogens. There are two in carbonic acid, H₂CO₃, and three in phosphoric acid, H ₃PO ₄. For any such multiple hydrogen acid, the first hydrogen is most easily removed, and the last hydrogen is removed with the greatest difficulty. These acids are called polyprotic (many protons) acids. The multiple acid ionization constants for each acid measure the degree of dissociation of the successive hydrogens.
Step 1
Polyprotic acid is an acid that can donate two or more H+ ion per molecule. Sulfurous acid donates two hydrogen ions in an aqueous solution.
Step 2
Dissociation of sulfurous acid in aqueous solution takes place in two steps. In the first step, one H⁺ ion is donated during dissociation forming HSO₃⁻.
H₂SO₃₍aq₎ +H₂O₍₁₎→HSO₃⁻₍aq₎
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Step 3
In the second step, one H+ ion is donated from HSO3- ion f...
H₂SO₃₍aq₎ +H₂O₍₁₎→SO₃²⁻₍aq₎+H₃O⁺₍aq₎
Answer:
<h3>The answer is 900 J</h3>
Explanation:
The potential energy of a body can be found by using the formula
PE = mgh
where
m is the mass
h is the height
g is the acceleration due to gravity which is 10 m/s²
From the question we have
PE = 45 × 10 × 2
We have the final answer as
<h3>900 J</h3>
Hope this helps you
