Answer:
The appropriate answer is "9.225 g".
Explanation:
Given:
Required level,
= 63 ppm
Initial concentration,
= 22 ppm
Now,
The amount of free SO₂ will be:
=
=
=
The amount of free SO₂ to be added will be:
=
=
∵ 1000 mg = 1 g
So,
=
=
Thus,
"9.225 g" should be added.
Answer & Explanation:
The molar mass of calcium chloride is 110.98 g/mol. We can use this information to solve this problem. We can set up our equation like this..
Multiply straight across on the top and straight across on the bottom.
Now divide.
So, there are 3.00 moles of calcium chloride contained in a 33 gram sample which is answer choice D.