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Dmitry_Shevchenko [17]
2 years ago
9

How many protons are in an element with an atomic number of 8 and a mass of 18?

Chemistry
2 answers:
lesantik [10]2 years ago
8 0
B.8 because protons are the same as electrons and the atomic number.

Hoped I helped!
Pachacha [2.7K]2 years ago
4 0
B: 8 the amount of protons is equal to the atomic number
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Need help balancing equations please.
densk [106]

Answer:

A, 4,3,2

B, 1,1,2

C, 1,1,1,2

3 0
3 years ago
Give me number of significant figures in the number 40
dangina [55]

1 significant figure, because there is no decimal after the zero the zero doesn't count.

5 0
3 years ago
1. Chemical equilibrium is established when the number of reactants equals the number of products.. . - True. - False. . 2. Acco
torisob [31]
<span>1)false a in chemical equilibrium concentration of reactant is equal to concentration of product
 2)as here they said heat is added in product side means its endothermic reaction and in endothermic reaction on increasing temp. equilibrium shift towards forward direction so its true
 3) B)as here mole are equal in reactant and product side that is 2 and if we increase pressure equilibrium shift in dat direction where no. of moles are less and here mole are equal so it will remain unaffected</span>
7 0
3 years ago
Read 2 more answers
A solution of acetic acid and water contains 205.0 g L-1 of acetic acid and 820.0 g L-1 of water. Compute the density of the sol
LekaFEV [45]

Answer:

\rho_t=1025000 gmL^{-1}

Explanation:

From the question we are told that:

Density of acetic acid \rho_a=205 gL^{-1}

Density of Water \rho_w=820 gL^{-1}

Generally the equation for Solution Density is mathematically given by

\rho_t= \rho_w+\rho_a

\rho_t=205+820

\rho_t=1025 gL^{-1}

\rho_t=1025000 gmL^{-1}

6 0
2 years ago
Suppose you want to create a 6 ng/μL solution in a 25 mL volumetric flask. However, this concentration cannot really be accurate
Over [174]

Answer:

Mass of chemical = 1.5 mg

Explanation:

Step 1: First calculate the concentration of the stock solution required to make the final solution.

Using C1V1 = C2V2

C1 = concentration of the stock solution; V1 = volume of stock solution; C2 = concentration of final solution; V2 = volume of final solution

C1 = C2V2/V1

C1 = (6 * 25)/ 0.1

C1 = 1500 ng/μL = 1.5 μg/μL

Step 2: Mass of chemical added:

Mass of sample = concentration * volume

Concentration of stock = 1.5 μg/μL; volume of stock = 10 mL = 10^6 μL

Mass of stock = 1.5 μg/μL * 10^6 μL = 1.5 * 10^6 μg = 1.5 mg

Therefore, mass of sample = 1.5 mg

4 0
2 years ago
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