Which taxonomic level includes the broadest characteristics?

Which element is most likely to allow electricity to pass through it?

yKpoI14uk [10]

Hello,
I have attached a periodic table to allow you to further understand my answer. We know elements are categorized in groups of Metals, Nonmetals, and metalloids. Let’s analyze each element. Sulfur is a nonmetal which mean it does not conduct well and does not have a good appearance, the same applies to all the other non metals on this list, including sulfur and helium. Copper is our only answer in which it fits and electricity can pass through/conduct easily. So our answer is copper. I hope this helps you with your assignment.

4 0

3 years ago

Read 2 more answers

A chemist prepares a solution of barium chloride by measuring out of barium chloride into a volumetric flask and filling the fla

mezya [45]

The given question is incomplete. The complete question is:

A chemist prepares a solution of barium chloride by measuring out 110 g of barium chloride into a 440 ml volumetric flask and filling the flask to the mark with water. Calculate the concentration in mole per liter of the chemist's barium chloride solution. Round your answer to 3 significant digits.

Answer: Concentration of the chemist's barium chloride solution is 1.20 mol/L

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

$Molarity=\frac{n\times }{V_s}$

where,

n = moles of solute

$V_s$ = volume of solution in L

moles of $BaCl_2$ (solute) = $\frac{\text {given mass}}{\text {Molar Mass}}=\frac{110g}{208g/mol}=0.529mol$

Now put all the given values in the formula of molality, we get

$Molality=\frac{0.529\times 1000}{440ml}=1.20mole/L$

Therefore, the molarity of solution is 1.20 mol/L

8 0

3 years ago

Consider the reaction: A (aq) ⇌ B (aq) at 253 K where the initial concentration of A = 1.00 M and the initial concentration of B

Ugo [173]

Answer:

The maximum amount of work that can be done by this system is -2.71 kJ/mol

Explanation:

Maximum amount of work denoted change in gibbs free energy $(\Delta G)$ during the reaction.

Equilibrium concentration of B = 0.357 M

So equilibrium concentration of A = (1-0.357) M = 0.643 M

So equilibrium constant at 253 K, $K_{eq}= \frac{[B]}{[A]}$

[A] and [B] represent equilibrium concentrations

$K_{eq}=\frac{0.357}{0.643}=0.555$

When concentration of A = 0.867 M then B = (1-0.867) M = 0.133 M

So reaction quotient at this situation, $Q=\frac{0.133}{0.867}=0.153$

We know, $\Delta G=RTln(\frac{Q}{K_{eq}})$

where R is gas constant and T is temperature in kelvin

Here R is 8.314 J/(mol.K), T is 253 K, Q is 0.153 and $K_{eq}$ is 0.555

So, $\Delta G=8.314\times 253\times ln(\frac{0.153}{0.555})mol/K$

= -2710 J/mol

= -2.71 kJ/mol

4 0

3 years ago

Lanthanides and actinides are kept separately in the periodic table. why?

liberstina [14]

The lanthanides and actinides are separated from the rest of the periodic table, usually appearing as separate rows at the bottom. The reason for this placement has to do with the electron configurations of these elements.

6 0

3 years ago

An electron confined in a one-dimensional box is observed, at different times, to have energies of 12 eV, 27 eV, and 48 eV. What

Fynjy0 [20]

Answer:

$l=3.5*10^{-10}m$