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Inessa [10]
3 years ago
15

What was ernest rutherfords experiment

Chemistry
1 answer:
ohaa [14]3 years ago
6 0

Answer: he shot tiny alpha particles throug a piece of gold foil.

Explanation:

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Name a type of asteroid and give a description.
IceJOKER [234]

Answer:

S-type or silaceous asteroids are made up primarily of stony materials and nickel-iron. They inhabit the inner Asteroid Belt. M-type, or metallic, are made up mostly of nickel-iron, and are found in the middle region of the Asteroid Belt

Explanation:

3 0
4 years ago
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How many nonreactive elements are there in the periodic table??
pochemuha

Answer:

6

Explanation:

All noble gases are nonreactive, these include helium (He), neon (Ne), argon (Ar), krypton (Kr), xenon (Xe), and radon (Rn).

5 0
4 years ago
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A recipe for bread states that the dough must bake for 40 minutes at a temperature of 190°C. The oven you are using has temperat
Mila [183]

Answer:

374°F

463.15K

Explanation:

This particular Question wants to test knowledge on the conversion of the units of temperature from celsius degree to degree Fahrenheit. Also, the conversion of degree celsius to kelvin.

The value given which is 190 degree celsius can be converted into degree Fahrenheit using the formula below;

(x°C × 9/5 ) + 32.

Therefore, x = 190°C =( 190°°C × 9/5) + 32 = 374°F.

The conversion of degree celsius to kelvin is given below as;

x°C + 273.15 .

Therefore, x = 190°C = 190°C + 273.15 = 463.15K.

Therefore, the temperature needed to bake at Fahrenheit and kelvin are 374°F and 463.15K respectively.

8 0
3 years ago
Select the correct answer.
sergey [27]
I believe the correct answer is B
8 0
3 years ago
10) How many grams are there in 1.00 x 10^24 molecules of BC13?
lana66690 [7]

194.5 g of BCl₃ is present in 1 × 10²⁴ molecules of BCl₃.

Explanation:

In order to convert the given number of molecules of BCl₃ to grams, first we have to convert the molecules to moles.

It is known that 1 moles of any element has 6.022×10²³ molecules.

Then 1 molecule will have \frac{1}{6.022*10^{23} } moles.

So 1*10^{24} molecules = \frac{1*10^{24} }{6.022*10^{23} } =1.66 moles

Thus, 1.66 moles are included in BCl₃.

Then in order to convert it from moles to grams, we have to multiply it with the molecular mass of the compound.

As it is known as 1 mole contains molecular mass of the compound.

As the molecular mass of BCl₃ will be

Molecular mass of BCl_{3}= Mass of Boron + (3*Mass of chlorine)

Mass of boron is 10.811 g and the mass of chlorine is 35.453 g.

Molar mass of BCl₃ = 10.811+(3×35.453)=117.17 g.

grams of BCl_{3}=Molar mass of BCl_{3}*Number of moles

grams of BCl_{3}=117.17*1.66=194.5 g

So, 194.5 g of BCl₃ is present in 1 × 10²⁴ molecules of BCl₃.

3 0
4 years ago
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