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tatiyna
3 years ago
6

For a certain chemical reaction, the standard Gibbs free energy of reaction at 30.0 °C is 110. kJ. Calculate the equlilibriunm c

onstant K for this reaction. Round your answer to 2 significant digits.
Chemistry
1 answer:
mestny [16]3 years ago
7 0

Answer:

Explanation:

The equation that relates standard Gibbs free energy, ΔG, with equilibrium constant, K, is:

ΔG = -RT ln K

<em>Where R is gas constant, 8.314J/molK, and T is absolute temperatue (30.0°C + 273.15 = 303.15K).</em>

<em />

Replacing (110kJ = 110000J):

110000J/mol = -8.314J/molK*303.15K ln K

-43.644 = lnK

1.11x10⁻¹⁹ = K

<em />

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Suppose you were required to make a solution by diluting 20.0 mL of an aqueous solution to a final volume of 750 mL.
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When calcium carbonate is added to hydrochloric acid, calcium chloride, carbon dioxide, and water are produced.
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CaCO is presewnt in excess.

Mass of of CaCO₃ remain unreacted =  7.007 g

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Mass of calcium chloride produced = ?

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CaCO₃ + 2HCl  →  CaCl₂  + H₂O + CO₂

Number of moles of CaCO₃:

Number of moles of CaCO₃ = Mass /molar mass

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Number of moles of HCl = 0.36 mol

Now we will compare the moles of CaCl₂ with HCl and CaCO₃ .

                  CaCO₃         :               CaCl₂

                    1                 :               1

                 0.25              :            0.25

                HCl                :                CaCl₂

                 2                   :                    1

                 0.36            :                  1/2 × 0.36 = 0.18 mol

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Mass of CaCl₂ = moles × molar mass

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                 2                   :                    1

                 0.36            :                  1/2 × 0.36 = 0.18 mol

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Mass of of CaCO₃ remain unreacted = 0.07 mol × 100.1 g/mol

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