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tatiyna
3 years ago
6

For a certain chemical reaction, the standard Gibbs free energy of reaction at 30.0 °C is 110. kJ. Calculate the equlilibriunm c

onstant K for this reaction. Round your answer to 2 significant digits.
Chemistry
1 answer:
mestny [16]3 years ago
7 0

Answer:

Explanation:

The equation that relates standard Gibbs free energy, ΔG, with equilibrium constant, K, is:

ΔG = -RT ln K

<em>Where R is gas constant, 8.314J/molK, and T is absolute temperatue (30.0°C + 273.15 = 303.15K).</em>

<em />

Replacing (110kJ = 110000J):

110000J/mol = -8.314J/molK*303.15K ln K

-43.644 = lnK

1.11x10⁻¹⁹ = K

<em />

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Answer:

Exergonic ,Endergonic,low concentration area,high

Explanation:

In exergonic reaction,certain molecules are broken down;in the process they release energy which is captured when high energy molecules(such as ATP and NADH) are formed.

                          The breakdown of these molecules can be coupled to thermodynamically unfavorable processes such as Endergonic reactions or pumping og hydrogen ion from low concentration areas to high concentration areas.

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They are due to past earthquakes

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What does the second law of thermodynamics say about entropy?
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Plants undergo photosynthesis to produce glucose according to the reaction below. What mass of water is required to produce 5.0g
solniwko [45]

Answer:

option a) 3 g

Explanation:

mass of Glucose = 5 g

Mass of H₂O = ?

Reaction Given:

                   6CO₂ + 6H₂O ----> C₆H₁₂O₆ + 6O₂

Solution:

First we have to find mass of glucose from balanced reaction.

So,

Look at the reaction

                        6CO₂ + 6H₂O -------> C₆H₁₂O₆ + 6O₂

                                     6 mol               1 mol

As 6 mole of water (H₂O) give 1 mole of Glucose (C₆H₁₂O₆ )

Convert moles to mass

molar mass of C₆H₁₂O₆  = 6(12) + 12(1) + 6(16)

molar mass of C₆H₁₂O₆  = 72 + 12 + 96

molar mass of C₆H₁₂O₆= 180 g/mol

molar mass of H₂O = 2(1) + 16 = 18 g/mol

Now

             6CO₂      +  6H₂O          --------->     C₆H₁₂O₆   +    6O₂

                              6 mol (18 g/mol)           1 mol (180 g/mol)

                                  108 g                            180 g

108 g of water (H₂O) produce 180 g of glucose (C₆H₁₂O₆)

So

if 108 g of water (H₂O) produce 180 g of glucose (C₆H₁₂O₆) so how many grams of water (H₂O) will be required to produce 5 g of glucose (C₆H₁₂O₆).

Apply Unity Formula

               108 g of water (H₂O) ≅ 180 g of glucose (C₆H₁₂O₆)

                X g of water (H₂O) ≅ 5 g of glucose (C₆H₁₂O₆)

Do cross multiply

                     mass of water (H₂O) = 108 g x 5 g / 180 g

                     mass of water (H₂O) = 3 g

So 3 g of water is required to produce 5 g of glucose.  

7 0
3 years ago
In the world of chemistry, a 'mole' is a number of something... a very large number of something.
kipiarov [429]

Given:

No of atoms present= 8.022 x 10^23 atoms

Now we know that 1 mole= 6.022 x 10^23 atoms


Hence number of moles present in 8.022 x 10^23 atoms is calculated as below.

Number of moles

= 8.022 x 10^23/6.022x 10^23

=1.3 moles.

Hence we have 1.3 moles present.

3 0
3 years ago
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