Answer:
a. There is a force on Jupiter toward the center of the orbit.
d. Jupiter is accelerating toward the center of the orbit.
Explanation:
Let us look at each of the choices one by one:
a. There is a force on Jupiter toward the center of the orbit.
True. The sun being at the center of Jupiter's orbit, pulls the planet towards it (providing the centripetal force), therefore, there exists a force on Jupiter toward the center of the orbit.
b. There is a force on Jupiter pulling it out from the center of the orbit.
Nope. The centripetal force due to gravity acts towards the center of the orbit.
c. There is a force on Jupiter in the direction of its motion.
Nope. There exists only the centripetal force acting towards the center of the orbit,
d. Jupiter is accelerating toward the center of the orbit.
Yes. Because of the centripetal force gravity provides, Jupiter is accelerating towards the center of the orbit, but it does not fall in because it has velocity perpendicular to the direction of its acceleration.
Step 1: Find the upward acceleration.
d = 107 m
a = ???
vi = 0
t = 14.4 sec
d = vi * t + 1/2 at^2
107 = 1/2 a * 14.4^2
a = 214 / (14.4)^2
a = 1.03 m/s^2
Step 2: Find the Volume of the balloon and from that the mass.
V = 4/3 * pi * r^3
r = 6.52 m
V = 4/3 x pi x 6.52^3
V= 1,161 m^3.
Density of air = m/V 1.29 = m/ 1161
M = 1.29 x 1161
m = 1498 kg
Step 3: The force keeping this in equilibrium = F = m* g
F = 1498 * 9.81 = 14692 N
Step 4: Find the mass needed to cause the upward acceleration.
14692 = (1498 - x) * (9.81 + 1.03)
14692 = (1498 - x) * 10.84 Divide both sides by 10.84
1355.35 = 1022 - x
1355.35 - 1022
x = 333.35 kg
There are multiple uses of nuclear energy, one of which is these uses is (A) radioisotope used as tracers in industry<span>. A radioactive isotope is injected into the patient's area of interest, for example the bowel, and the movement of the radioactive isotope is tracked using the radiation it emits.</span>
To solve this problem it is necessary to take into account the concepts related to the magnetic moment and the torque applied over magnetic moments.
For the case of the magnetic moment of a loop we have to,
Where
I = Current
A = Area of the loop
Moreover the torque exerted by the magnetic field is defined as,
Where,
I = Current
A = Area of the loop
B = Magnetic Field
PART A) First we need to find the perimeter, then
The total Area of the loop would be given as,
Substituting at the equation of magnetic moment we have
Therefore the magnetic moment of the loop is 
PART B) Replacing our values at the equation of torque we have that
Therefore the torque exerted by the magnetic field is 
A hammer pounding a nail into a board is an example of Newton’s Third law.
Newton’s third law states that for every action there is an equal and opposite reaction. Meaning, when you hit the hammer on the board the same amount of energy that is going into the board, is going into the hammer. Causing the hammer to bounce off the board.
Hope this helps!
