Question

A football player threw a ball upward at an angle or 24 degrees with the horizontal with A velocity of 18 m/s. What are the vertical and horizontal components of the ball’s velocity?

Answer 1

Answer:

$V_y = 16.44\ m/s$

$V_y = 7.32\ m/s$

Explanation:

Given

$\theta = 24$

$Velocity\ (V) = 18m/s$

Required

Determine the vertical and horizontal components

The vertical (Vy) and horizontal (Vx) components is calculated as thus:

$V_x = Vcos\theta$

$V_y = Vsin\theta$

Calculating Vertical Components:

$V_y = Vsin\theta$

$V_y = 18 * sin24$

$V_y = 18 * 0.40673664307$

$V_y = 7.32125957526$

$V_y = 7.32\ m/s$ --- Approximated

Calculating Horizontal Components:

$V_x = Vcos\theta$

$V_x = 18 * cos24$

$V_x = 18 * 0.91354545764$

$V_x = 16.4438182375$

$V_x = 16.44\ m/s$ --- Approximated