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Elza [17]
3 years ago
13

A football player threw a ball upward at an angle or 24 degrees with the horizontal with A velocity of 18 m/s. What are the vert

ical and horizontal components of the ball’s velocity?
Physics
1 answer:
svet-max [94.6K]3 years ago
4 0

Answer:

V_y = 16.44\ m/s

V_y = 7.32\ m/s<em />

Explanation:

Given

\theta = 24

Velocity\ (V) = 18m/s

Required

Determine the vertical and horizontal components

The vertical (Vy) and horizontal (Vx) components is calculated as thus:

V_x = Vcos\theta

V_y = Vsin\theta

Calculating Vertical Components:

V_y = Vsin\theta

V_y = 18 * sin24

V_y = 18 * 0.40673664307

V_y = 7.32125957526

V_y = 7.32\ m/s<em> --- Approximated</em>

Calculating Horizontal Components:

V_x = Vcos\theta

V_x = 18 * cos24

V_x = 18 * 0.91354545764

V_x = 16.4438182375

V_x = 16.44\ m/s <em>--- Approximated</em>

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4 years ago
A soccer player kicks a rock horizontally off a 37 m high cliff into a pool of water. If the player hears the sound of the splas
Alchen [17]
<h2>Answer:</h2>

<em><u>(a). 16.741 m/s</u></em>

<em><u>(b). 15.75 m/s</u></em>

<h2>Explanation:</h2>

In the question,

Height of the cliff, h = 37 m

Time taken to reach the sound to us = 2.92 s

Speed of the sound in air at room temperature = 343 m/s

Now,

Let us say the speed of the ball = u m/s

So,

Time taken by the ball to reach at the bottom, t is given by,

t=\sqrt{\frac{2h}{g}}\\t=\sqrt{\frac{2\times 37}{9.8}}\\t=2.747\,s

So,

Splash is heard after = 2.92 s

So,

<u>Time taken by sound to travel the shortest distance along the hypotenuse of the triangle</u> thus formed is,

t = 2.92 - 2.747

t = 0.172 s

Now,

Distance traveled by sound is given by,

Distance=343\times 0.172\\Distance=59.02\,m

So,

In the triangle using the Pythagoras Theorem,

Horizontal distance traveled is,

D=\sqrt{59.02^{2}-37^{2}}\\D=45.99\,m

So,

Speed of throwing of ball is given by,

Distance=Speed\times Time\\45.99=u\times 2.747\\u=16.741\,m/s

<em><u>Therefore, the speed of the ball = 16.741 m/s.</u></em>

(b).

If,

Speed of sound = 331 m/s

So,

<u>Distance traveled by sound</u> is,

Distance=331\times 0.172\\Distance=56.932\,m

So,

Distance traveled in the horizontal by ball is,

Distance=\sqrt{56.932^{2}-37^{2}}\\Distance=43.269\,m

So,

Speed of the ball thrown is given by,

Speed=\frac{Distance}{Time}\\Speed=\frac{43.269}{2.747}\\Speed=15.75\,m/s

<em><u>Therefore, the speed of the ball = 15.75 m/s.</u></em>

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the awnser is yes because when I did this assignment I got an A

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Why does a box on the seat of a car slide around on the c one the car speeds up slows down or turns a corner?
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Because the box keeps going straight at the same speed, while the seat under it speeds up, slows down, or changes direction.
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During the fission reaction shown, how did the target nucleus change ?
Zarrin [17]

Answer:

A. The target nucleus split into two nuclei, each with fewer nucleons than the original.

Explanation:

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