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Elenna [48]
3 years ago
5

A wave created by a certain source travels from medium 1 into another medium 2. It is noticed that its velocity is faster in med

ium 2 than in medium 1
Physics
1 answer:
Finger [1]3 years ago
4 0
Do you have a chart or something that goes with it?

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An arthroscope can be inserted into a knee joint through a very tiny incision to help a doctor examine the knee. A light is tran
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Sample Response: The technology being described is fiber optics. Since they are small and flexible, they enable doctors to see areas that they might otherwise be unable to see without surgery.

4 0
3 years ago
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To form a hydrogen atom, a proton is fixed at a point and an electron is brought from far away to a distance of 0.529 ✕ 10−10 m,
Elodia [21]
1) First of all, let's calculate the potential difference between the initial point (infinite) and the final point (d=0.529x10-10 m) of the electron.
This is given by:
\Delta V =- \int\limits^{d}_{\infty} {E} \, dr
Where E is the electric field generated by the proton, which is
E=k_e  \frac{q}{r^2} 
where k_e=8.99\cdot10^9~Nm^2C^{-2} is the Coulomb constant and q=1.6\cdot10^{-19}~C is the proton charge.
Replacing the electric field formula inside the integral, we obtain
\Delta V =- \int\limits^{d}_{\infty} {k_e  \frac{q}{r^2} } \, dr = k_e  \frac{q}{d}= 27~V

2) Then, we can calculate the work done by the electric field to move the electron (charge q_e=-1.6\cdot10^{-19}C) through this \Delta V. The work is given by
W=-q_e \Delta V = - (-1.6\cdot10^{-19}C) (27V)=4.35\cdot10^{-18}~J

5 0
3 years ago
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A rocket burns fuel at a rate of 249 kg/s and exhausts the gas at a relative speed of 2 km/s. Find the thrust of the rocket. Ans
tino4ka555 [31]
1.791MN is the answer
8 0
3 years ago
If the mass of a material is 115 grams and the volume of the material is 16 cm3, what would the density of the material be?
hjlf
Well, density is mass/volume. So what's 115 g / 16 cm3? That'll get you your density. Remember that density will be in g/cm3! 
6 0
3 years ago
A 75.0 kg object decelerates from a speed of 100 m/s to 50 m/s over an interval of 25 seconds. What was the net force acting upo
lukranit [14]

Assuming constant acceleration <em>a</em>, the object has undergoes an acceleration of

<em>a</em> = (50 m/s - 100 m/s) / (25 s) = -2 m/s²

Then the net force has a magnitude <em>F</em> such that, by Newton's second law,

<em>F</em> = (75.0 kg) <em>a</em>

<em>F</em> = (75.0 kg) (-2 m/s²)

<em>F</em> = -150 N

meaning the object is acted upon by a net force of 150 N in the direction opposite the initial direction in which the object is moving.

7 0
3 years ago
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