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Elenna [48]
2 years ago
5

A wave created by a certain source travels from medium 1 into another medium 2. It is noticed that its velocity is faster in med

ium 2 than in medium 1
Physics
1 answer:
Finger [1]2 years ago
4 0
Do you have a chart or something that goes with it?

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A coiled spring with coils that are closely spaced then widely then closely then widely then closely, ending with a yellow line
liberstina [14]

Answer:

2, sorry I'm late but my answer is right, I just took the quiz

4 0
3 years ago
Read 2 more answers
In a hospital setting, which of the following presents the possibility of being the source of an arc flash?
Alja [10]
The answer to this question would be <span>Electrocautery Device

In a hospital, the device that can cause arc flash would be an electrocautery device or a circuit breaker. In fact, the electrocautery device is using the arc flash principle to work. The arc flash will cause burns that surgeon use to clot bleeding in surgery or to destroy a tissue.</span>
6 0
3 years ago
A 20-kg rock sits atop a 30 meter cliff. How much potential energy does it have?
Brut [27]
Gravitational potential energy ...

=  (mass) x (acceleration of gravity) x (height)

=  (20 kg) x (9.8 m/s²) x (30 m)

=   (20 x 9.8 x 30)  kg-m²/sec²

=   5,880 joules
6 0
3 years ago
A change
Tamiku [17]

The work done if the forklift is operating at full capacity is 11,900 J.

We have to recall that power is defined as the rate of doing work. The rate of doing work is defined as;

Power = Work done/time taken

When;

Power = 4950 W

Time taken = 2.40 s

Work done = Power × time taken

Work done = 4950 W × 2.40 s

Work done = 11,900 J

Learn more about work done: brainly.com/question/3902440

5 0
2 years ago
A sound wave traveling at 342 m/s is emitted by the foghorn of a tugboat. an echo is heard 3.20 s later. how far away is the ref
Mice21 [21]
Let's call L the distance between the tugboat and the reflecting object. The sound wave travels from the tugboat to the reflecting object, and then back again to the tugboat, in a total time of t=3.20 s. This means that the distance covered during this time is S=2L.

The sound wave moves by uniform motion, with velocity v=342 m/s, so we can use the basic relationship between space and time for a uniform motion:
S=vt = (342 m/s)(3.20 s)=1094.4 m

And so the distance L between the tugboat and the reflecting object is
L= \frac{S}{2}= \frac{1094.4 m}{2}=547.2 m
7 0
3 years ago
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