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Contact [7]
3 years ago
15

Which statement describes a chemical reaction?

Chemistry
2 answers:
SpyIntel [72]3 years ago
4 0
The answer I would have to say would possibly be C
Ivan3 years ago
4 0

this is correct: Atoms in the reactants are rearranged to form new substances

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PLEASE AWNSER THIS ASAP!!! 100points! i will give brainliest please awnser right!!!
GaryK [48]

Answer: How does cellar respiration the law of converter of mass and the law of conversion of energy?

Explanation:  Conservation of mass is the first law of thermodynamics. This states that energy is conserved in all processes, since it cannot be created nor destroyed. This applies to photosynthesis and cellular respiration.

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Which chemical is the limiting reagent for the entire series of reactions? Why?
Reptile [31]
I'm assuming that you are asking a general question because you did not include an example.

The limiting reagent is the item in the reactants (reagents) that will run out first. This is because it limits what the reaction can produce, essentially causing the leftover elements/compounds to just sit there.
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4 years ago
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Three friends were kicking soccer balls at a neighborhood field. Three soccer balls were rolling across the field. The black soc
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3 years ago
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Does it take more, less, or the same amount of heat to melt 1.0 kg of ice at 0°C, or to bring 1.0 kg of liquid water at 0°C to t
Murljashka [212]

Answer : It takes less amount of heat to metal 1.0 Kg of ice.

Solution :

The process involved in this problem are :

(1):H_2O(s)(0^oC)\rightarrow H_2O(l)(0^oC)\\\\(2):H_2O(l)(0^oC)\rightarrow H_2O(l)(100^oC)

Now we have to calculate the amount of heat released or absorbed in both processes.

<u>For process 1 :</u>

Q_1=m\times \Delta H_{fusion}

where,

Q_1 = amount of heat absorbed = ?

m = mass of water or ice = 1.0 Kg

\Delta H_{fusion} = enthalpy change for fusion = 3.35\times 10^5J/Kg

Now put all the given values in Q_1, we get:

Q_1=1.0Kg\times 3.35\times 10^5J/Kg=3.35\times 10^5J

<u>For process 2 :</u>

Q_2=m\times c_{p,l}\times (T_{final}-T_{initial})

where,

Q_2 = amount of heat absorbed = ?

m = mass of water = 1.0 Kg

c_{p,l} = specific heat of liquid water = 4186J/Kg^oC

T_1 = initial temperature = 0^oC

T_2 = final temperature = 100^oC

Now put all the given values in Q_2, we get:

Q_2=1.0Kg\times 4186J/Kg^oC\times (100-0)^oC

Q_2=4.186\times 10^5J

From this we conclude that, Q_1 that means it takes less amount of heat to metal 1.0 Kg of ice.

Hence, the it takes less amount of heat to metal 1.0 Kg of ice.

5 0
3 years ago
What is the mass of one mole of H2o
puteri [66]

Answer:the answer is 18.01528

Explanation:

5 0
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