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Viktor [21]
4 years ago
8

Rank the following alkyl halides from most reactive to least reactive in an SN1 reaction: 2-bromo-2-methylpentane, 2-chloro-2-me

thylpentane, 3-chloropentane, and 2-iodo-2-methylpentane. Rank the alkyl halides from most reactive to least reactive. To rank items as equivalent, overlap them. ResetHelp Least reactiveMost reactive

Chemistry
1 answer:
MariettaO [177]4 years ago
3 0

Answer:

2-iodo-2-methylpentane > 2-bromo-2-methylpentane > 2-chloro-2-methylpentane > 2-chloro-2-methylpentane

Explanation:

In this case, the<u> Sn1 reaction</u> would form a <u>carbocation</u>. So, the molecule that can generate a <u>very stable carbocation</u> will be more reactive.  We have to remember that <u>tertiary carbocations</u> are the more stable ones. With this in mind, 3-chloropentane would be the <u>least reactive</u> molecules of all.

Then to decide which one is more reactive between the other ones, we have to check the <u>leaving group</u>. In this case, all the atoms are <u>halogens</u>, so if we have a <u>larger atom</u> the leaving group would leave <u>more easily</u>.

With his in mind the larger atom would be I, then Br and finally Cl, therefore the 2-iodo-2-methylpentane would be the <u>more reactive one.</u>

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Nicotine, a component of tobacco, is composed of c, h, and n. a 4.200-mg sample of nicotine was combusted, producing 11.394 mg o
Rudiy27

Answer:

            Empirical Formula  =  C₅H₇N₁

Solution:

Data Given:

                      Mass of Nicotine  =  4.20 mg  =  0.0042 g

                      Mass of CO₂  =  11.394 mg  =  0.011394 g

                      Mass of H₂O  =  3.266 mg  =  0.003266 g

Step 1: Calculate %age of Elements as;

                      %C  =  (mass of CO₂ ÷ Mass of sample) × (12 ÷ 44) × 100

                      %C  =  (0.011394 ÷ 0.0042) × (12 ÷ 44) × 100

                      %C  =  (2.7128) × (12 ÷ 44) × 100

                      %C  =  2.7128 × 0.2727 × 100

                      %C  =  73.979 %


                      %H  =  (mass of H₂O ÷ Mass of sample) × (2.02 ÷ 18.02) × 100

                      %H  =  (0.003266 ÷ 0.0042) × (2.02 ÷ 18.02) × 100

                      %H  =  (0.7776) × (2.02 ÷ 18.02) × 100

                      %H  =  0.7776 × 0.1120 × 100

                      %H  =  8.709 %


                      %N  =  100% - (%C + %H)

                      %N  =  100% - (73.979 % + 8.709%)

                      %N  =  100% - 82.688%

                      %N  =  17.312 %

Step 2: Calculate Moles of each Element;

                      Moles of C  =  %C ÷ At.Mass of C

                      Moles of C  = 73.979 ÷ 12.01

                     Moles of C  =  6.1597 mol


                      Moles of H  =  %H ÷ At.Mass of H

                      Moles of H  = 8.709 ÷ 1.01

                      Moles of H  =  8.6227 mol


                      Moles of N  =  %N ÷ At.Mass of O

                      Moles of N  = 17.312 ÷ 14.01

                      Moles of N  =  1.2356 mol

Step 3: Find out mole ratio and simplify it;

                C                                        H                                     N

            6.1597                               8.6227                             1.2356

     6.1597/1.2356                  8.6227/1.2356                 1.2356/1.2356

               4.985                             6.978                                   1

             ≈ 5                                      ≈ 7                                     1

Result:

        Empirical Formula  =  C₅H₇N₁

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By definition, we have to:
A molecule is a group of at least two atoms in a defined configuration linked by chemical bonds.
We have two types of molecules:
1) several atoms of a single chemical element, as in the case of oxygen. (O2)
2) Atoms of different elements, as in the case of water. (H2O)
Answer:
the best description of a molecule is:
A: A molecule of an element is composed of at least two types of atoms.
3 0
3 years ago
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