Answer:
6 stages
Explanation:
Given:
Copper ore contains:
4.3 wt% water
10.3 wt% CuSO₄
85.3 wt% rock
Feed rate = 11.7 tons per hour
solution produced is to be 10 wt% copper sulfate
90 wt% water
Now,
The CuSO₄ supplied through the feed = 10.3 wt% CuSO₄ × Feed rate
= 0.103 × 11.7
= 1.2051 tons per hour
also,
At each stage 2 tons of solution is collected
therefore,
The CuSO₄ collected in each stage
= weight of solution × 10 wt% copper sulfate
= 2 tons per hour × 0.1
= 0.2 tons per hour
also,
98% of the CuSO₄ is to be recovered
thus,
the amount of CuSO₄ to be recovered
= 0.98 × CuSO₄ supplied through the feed
= 0.98 × 1.2051 tons per hour
= 1.180998
Therefore,
The number of stages required = 
= 
= 5.90499 ≈ 6 stages
Answer:
Hello your question is poorly written below is the well written question
Uranium, an important component of both nuclear weapons and nuclear reactors, has two major isotopes, U-238, which has a half-life of approximately 4.5 billion years, and U-235, which has a half-life of approximately 700 million years. Both were present in equal amounts at the time of the creation of the Earth, 4.5 billion years ago. How many years after the creation of the Earth had the amount of radiation from uranium decayed to half the amount present at the time of the creation of the Earth
Answer : 140 billion years
Explanation:
Given that :
U-238 h1/2 = 4.5 billion years
U-235 h1/2 = 700 million years
At the beginning both Isotopes where present in equal amount
Determine the T years before the amount of Uranium decays to Half
T = ? N'2 = N1 / 2
we know that N = No ( 1/2 )^h where h = time / half-life time
attached below is the detailed solution of the given problem
The answer to this question is A
Answer is: 13181,7 kJ of energy <span>is released when 10.5 moles of acetylene is burned.
</span>Balanced chemical reaction: C₂H₂ + 5/2O₂ → 2CO₂ + H₂O.
<span>ΔHrxn = sum of
ΔHf (products of reaction) - sum of ΔHf (reactants).</span><span>
Or ΔHrxn = ∑ΔHf (products of reaction)
- ∑ΔHf (reactants).
ΔHrxn - enthalpy change of chemical reaction.
<span>ΔHf - enthalpy of formation of reactants or
products.
</span></span>ΔHrxn = (2·(-393,5) + (-241,8)) - 226,6 · kJ/mol.
ΔHrxn = -1255,4 kJ/mol.
Make proportion: 1 mol (C₂H₂) : -1255,4 kJ = 10,5 mol(C₂H₂) : Q.
Q = 13181,7 kJ.
Larger gases produces more spectral lines than the smaller gases because they have more orbitals in their atoms.
Hydrogen has only one orbital in which an electron orbits. At the excited state, that is, when the electron gains energy, the number of energy level it can transcend is very few. For larger elements, they have more orbitals and when excited, they can move from the ground state to other energy levels at which they produce various unique spectral lines.
