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Viktor [21]
4 years ago
8

Rank the following alkyl halides from most reactive to least reactive in an SN1 reaction: 2-bromo-2-methylpentane, 2-chloro-2-me

thylpentane, 3-chloropentane, and 2-iodo-2-methylpentane. Rank the alkyl halides from most reactive to least reactive. To rank items as equivalent, overlap them. ResetHelp Least reactiveMost reactive

Chemistry
1 answer:
MariettaO [177]4 years ago
3 0

Answer:

2-iodo-2-methylpentane > 2-bromo-2-methylpentane > 2-chloro-2-methylpentane > 2-chloro-2-methylpentane

Explanation:

In this case, the<u> Sn1 reaction</u> would form a <u>carbocation</u>. So, the molecule that can generate a <u>very stable carbocation</u> will be more reactive.  We have to remember that <u>tertiary carbocations</u> are the more stable ones. With this in mind, 3-chloropentane would be the <u>least reactive</u> molecules of all.

Then to decide which one is more reactive between the other ones, we have to check the <u>leaving group</u>. In this case, all the atoms are <u>halogens</u>, so if we have a <u>larger atom</u> the leaving group would leave <u>more easily</u>.

With his in mind the larger atom would be I, then Br and finally Cl, therefore the 2-iodo-2-methylpentane would be the <u>more reactive one.</u>

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<span>The atoms of a chemical element can exist in different types. These are calledisotopes. They have the same number of protons (and electrons), but different numbers of neutrons.</span>
5 0
4 years ago
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If O2O2 is collected over water at 40.0 ∘C∘C and a total pressure of 755 mmHgmmHg , what volume of gas will be collected for the
Semenov [28]

Answer:

The correct answer is 4.46 L.

Explanation:

Based on the given information, the mass of NiO given is 23.87 grams. The no. of moles can be determined by using the formula, n = weight/molecular mass. The molecular mass of NiO is 74.69 gram per mole. Now the moles of NiO will be,

Moles of NiO = 23.87 g/74.69 g/mol = 0.3196 moles

Now the moles of O2 will be = 1/2 * moles of NiO

= 1/2 * 0.3196 = 0.160 moles

The total pressure given in the question is 755 mmHg, and the vapor pressure mentioned is 55.4 mmHg. So, the pressure of O2 will be,

= Total pressure - Vapor pressure

= 755 mmHg - 55.4 mmHg

= 699.6 mmHg

= 699.6 * (1 atm / 760 mmHg)

= 0.9205 atm

Now the volume of the oxygen gas collected can be calculated by using the ideal gas law equation, that is, PV = nRT

0.9205 atm . V = 0.160 moles * 0.08206 L-atm/mol-K * 313 K (273 + 40 K)

V = 0.160 moles * 0.08206 L-atm/mol-K * 313 K / 0.9205 atm

V = 4.46 L

8 0
4 years ago
How can a saturated solution be made from the liquid from an eyedropper? Write the steps. Please help!
ololo11 [35]

Answer:

Add solute to liquid until dissolving stops.

Evaporate a solvent from a solution until the solute begins to crystallize or precipitate.

Add seed crystals to a solution that is supersaturated.

4 0
3 years ago
When aqueous solutions of sodium carbonate and zinc iodide are combined, solid zinc carbonate and a solution of sodium iodide ar
cestrela7 [59]

Answer:

CO₃²⁻ + Zn²⁺ → ZnCO₃(s)

Explanation:

The net ionic equation is defined as a chemical equation for a reaction that lists only those species participating in the reaction.

In the reaction of sodium carbonate (Na₂CO₃) with zinc iodide (ZnI₂) that produce solid zinc carbonate (ZnCO₃) and a solution of sodium iodide (NaI) the formula is:

2Na⁺ + CO₃²⁻ + Zn²⁺ + 2I⁻ → ZnCO₃(s) + 2Na⁺ + 2I⁻

The net ionic equation is:

<em> CO₃²⁻ + Zn²⁺ → ZnCO₃(s)</em>

<em></em>

I hope it helps!

4 0
3 years ago
A sample of Ar gas at 35°C occupies a volume of 1.50 L at a pressure of 3.2 atm. How many moles of the gas are present in the sa
Alex Ar [27]

The moles of the gas that  are  present  in  the sample  is  0.1898 moles


   <em><u>calculation</u></em>

  •  Use the Ideal  gas  equation

  that is PV=  nRT

 where  p (  pressure) = 3.2 atm

            V(  volume)  =  1.50 L

              n ( number of moles)  =?

               R ( gas constant)=   0.0821  atm.L/mol.K

              T(  temperature)=  35 +273 ==308  k

  •  make n  the subject of the formula   by diving  both side  by RT

     n =  Pv/RT

  n  is therefore=  [3.2 atm x 1.50 L)  / ( 0.0821  atm.L/mol.K x 308 K)= 0.1898 moles


3 0
3 years ago
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