Answer:
q = 38,5 kJ
Explanation:
In its melting point, at 0°C, water is liquid. The boiling point of water is 100°C. It is possible to estimate the heat you required to raise the temperature of water from 0°C to 100°C using:
q = C×m×ΔT
Where C is specific heat of water (4,184J/g°C), m is mass of water (92,0g) and ΔT is change in temperature (100°C-0°C = 100°C)
Replacing:
q = 4,184J/g°C×92,0g×100°C
q = 38493 J, in kilojoules:
<em>q = 38,5 kJ</em>
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I hope it helps!
Answer:
34.2 g is the mass of carbon dioxide gas one have in the container.
Explanation:
Moles of 
:-
Mass = 49.8 g
Molar mass of oxygen gas = 32 g/mol
The formula for the calculation of moles is shown below:
Thus,
Since pressure and volume are constant, we can use the Avogadro's law as:-
Given ,
V₂ is twice the volume of V₁
V₂ = 2V₁
n₁ = ?
n₂ = 1.55625 mol
Using above equation as:
n₁ = 0.778125 moles
Moles of carbon dioxide = 0.778125 moles
Molar mass of 
= 44.0 g/mol
Mass of = Moles × Molar mass = 0.778125 × 44.0 g = 34.2 g
<u>34.2 g is the mass of carbon dioxide gas one have in the container.</u>
Answer:
Vapor pressure of Eugenol = 667.04torr
Explanation:
By applying dalton's law of partial pressure;
at 100degree celsius, total pressure = 744.67torr
vapor pressure of water at 100 degree celsius = 760torr
mole fraction of eugenol = 0.1648
mole fraction of water = 1 - 0.1648 = 0.8352
Total pressure = vapor P(water) + vapor P( Eugenol)
for water; vapour pressure = mole fraction x total pressure
for eugenol; vapor pressure = mole fraction x total pressure
substituting into the above gives the vapor pressure of eugenol = 667.04torr
