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3 years ago

Pls tell me it’s a test-

Chemistry

2 answers:

Nina [5.8K]3 years ago

4 0

Answer:

It dissolves

Explanation:

Slav-nsk [51]3 years ago

3 0

Answer:

4. It dissolves

google told me so

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Disease caused by virus are more dangerous.Why?

nlexa [21]

Answer:

Explanation:

1. Virus's are hard to detect because of their simple construction.

2. Some mutate very easily.

3. It is hard to isolate the virus and kill it without doing damage to the host.

7 0

3 years ago

1.15 g of a metallic element reacts with 300 cm3 of oxygen at 298 K and 1 atm pressure, to form. an oxide which contains O2– ion

Deffense [45]

D sodium
hope it helps

5 0

3 years ago

A. The resistivity of aluminum is 2.8 x 10-8 Qm. What is the conductivity of aluminum?

kifflom [539]

Answer:

The resistivity of aluminum is 2.8 × 10–8m. What is the conductivity of aluminum? (2 points) Resistivity = 1 / conductivityx = 1/ 2.8 x 10^-8Resistivity= 36714285.71 Ohms 2.

4 0

3 years ago

ASAP!

Sav [38]

When a radioactive isotope releases an alpha particle, the atomic number of the atom is decreased by four.

So, the correct answer is B.

Hope this helps,

Davinia.

4 0

3 years ago

A radioisotope decays to give an alpha particle andPb-208.

oee [108]

Answer: The original element is $_{84}^{212}\textrm{Po}$

Explanation:

Alpha decay is defined as the process in which alpha particle is emitted. In this process, a heavier nuclei decays into a lighter nuclei. The alpha particle released carries a charge of +2 units.

The released alpha particle is also known as helium nucleus.

$_Z^A\textrm{X}\rightarrow _{Z-2}^{A-4}\textrm{Y}+_2^4\alpha$

For the given alpha decay process of an isotope:

$^{Z}_{A}\textrm{X}\rightarrow ^{208}_{82}\textrm{Pb}+_2^4\alpha$

To calculate A:

Total mass on reactant side = total mass on product side

A = 208 + 4

A = 212

To calculate Z:

Total atomic number on reactant side = total atomic number on product side

Z = 82 + 2

Z = 84

The isotopic symbol of unknown element is $_{84}^{212}\textrm{Po}$

Hence, the original element is $_{84}^{212}\textrm{Po}$

3 0

3 years ago