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3 years ago

Can someone help me please

Physics

1 answer:

Svetllana [295]3 years ago

6 0

Answer:

B.) Visit a healthcare professional

Explanation:

Their judgement is much better than a friend's or your own.

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(8c7p26) During spring semester at MIT, residents of the parallel buildings of the East Campus dorms battle one another with lar

likoan [24]

Answer: 1175 J

Explanation:

Hooke's Law states that "the strain in a solid is proportional to the applied stress within the elastic limit of that solid."

Given

Spring constant, k = 102 N/m

Extension of the hose, x = 4.8 m

from the question, x(f) = 0 and x(i) = maximum elongation = 4.8 m

Work done =

W = 1/2 k [x(i)² - x(f)²]

Since x(f) = 0, then

W = 1/2 k x(i)²

W = 1/2 * 102 * 4.8²

W = 1/2 * 102 * 23.04

W = 1/2 * 2350.08

W = 1175.04

W = 1175 J

Therefore, the hose does a work of exactly 1175 J on the balloon

7 0

3 years ago

A pump, submerged at the bottom of a well that is 35 m deep, is used to pump water uphill to a house that is 50 m above the top

Sidana [21]

Answer:

0.45

Explanation:

6 0

3 years ago

A 13.0-g wad of sticky clay is hurled horizontally at a 110-g wooden block initially at rest on a horizontal surface. The clay s

Alisiya [41]

Answer:

$v_{ic}=92.53 m/s$

Explanation:

We need to apply conservation of momentum and energy to solve this problem.

<u>Conservation of momentum</u>

$p_{i}=p_{f}$

$m_{c}v_{ic}=(m_{c}+m_{w})V$ (1)

m(c) is the mass of stick clay
m(w) is the mass of the wooden block
v(ic) is the initial velocity of clay
V is the final velocity of the system clay plus wood.

<u>Conservation of total energy</u>

The change in kinetic energy is equal to the change in internal energy, in our case it would be the energy loss due to the friction force. Let's recall the definition of work, it is the dot product between force and displacement, Therefore:

$\Delta E=W$

$\frac{1}{2}(m_{c}+m_{w})V^{2}=F_{friction}*d$

$\frac{1}{2}(m_{c}+m_{w})V^{2}=\mu (m_{c}+m_{w})gd$

We can find V from this equation:

$V=\sqrt{2\mu gd}=\sqrt{2*0.65*9.81*7.5}=9.78 m/s$

Now, let's put V into the equation (1) and find v(ic)

$v_{ic}=\frac{(m_{c}+m_{w})V}{m_{c}}=\frac{123*9.78}{13}=92.53 m/s$

I hope it helps you!

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8 0

3 years ago

How long does it take a 22 kW steam engine to do 5.6 × 107 J of work? Answer in units of s.

Lena [83]

<h2>Time needed is 2545.45 seconds.</h2>

Explanation:

We know equation for power

$\texttt{Power = }\frac{\texttt{Work}}{\texttt{Time}}$

Here we need to find time when for a 22 kW steam engine to do 5.6 × 10⁷ J of work.

Work = 5.6 × 10⁷ J

Power = 22 kW = 22 x 10³ W

Substituting

$\texttt{Power = }\frac{\texttt{Work}}{\texttt{Time}}\\\\22\times 10^3=\frac{5.6\times 10^7}{\texttt{Time}}\\\\\texttt{Time}=2545.45s$

Time needed is 2545.45 seconds.

5 0

3 years ago

A3 kg mass takes some impulse in order increase its velocity from 11

Butoxors [25]

Answer:

JAKSJAKZNPWLAQJZOAKZONZPW

THE ANSWER IS FAILURE

4 0

3 years ago

Can someone help me please ​

Can someone help me please