A substance has a mass of 2795 g and a volume of 312 cm

What is the net charge of both pantothenate and phosphopantothenate in aqueous solution at ph 7?.

wlad13 [49]

The net charge of pantothenate is -1 whereas the net charge of phosphopantothenate is −2 in aqueous solution at pH 7.

<h3>What is the net charge of both pantothenate and phosphopantothenate?</h3>

At pH 7, the carboxylic acid of pantothenate will lose one hydrogen ion which leads to a net charge of −1 on pantothenate while on the other hand, the phosphate group of phosphopantothenate will lose two hydrogen ions (−2) so −2 charge appear on the phosphopantothenate.

So we can conclude that The net charge of pantothenate is -1 whereas the net charge of phosphopantothenate is −2 in aqueous solution at pH 7.

Learn more about charge here: brainly.com/question/25923373

#SPJ1

4 0

2 years ago

An object accelerating only under the force of gravity is A) free fall or B) acceleration due to gravity

Andrews [41]

-- An object acted on by only the force of gravity, on or near Earth's surface,
accelerates downward at the rate of about 9.8 m/s² without air resistance.

-- That number is "the acceleration due to gravity, on Earth".

-- The object in that situation is said to be in "free fall".

3 0

3 years ago

HELP ASAP Miguel claims that as a ball falls, it loses potential energy. Izzy claims that as a ball falls, it

Bogdan [553]

Answer and Explanation:

They are both correct.

This is because potential energy is when there is potential for the object to have energy, while kinetic energy is energy that is moving already.

So, as the ball falls, it loses its potential energy, or "still/Stalled" energy, and gains kinetic energy, or moving energy.

#teamtrees #PAW (Plant And Water)

7 0

3 years ago

Betty weighs 400 N and she is sitting on a playground swing seat that hangs 0.21 m above the ground. Tom pulls the swing back an

disa [49]

Answer:

4.15 m/s

Explanation:

As the total energy must be conserved (neglecting air resistance) the change in gravitational potential energy, must be equal to the change in kinetic energy:

ΔE = ΔK + ΔU =0

If we take as a zero reference level for the gravitational potential energy, the height of the swing seat above the ground, (which is equal to 0.21 m), we can find the initial gravitational energy, considering the height of the point where the seat is released, regarding this point:

h₀ = 1.09 m -0.21 m = 0.88 m

⇒ U₀ = m*g*h₀ = 400 N*0.88 m = 352 J

As Uf = 0, ΔU = Uf -U₀ = -352 J

As the swing starts from rest, K₀=0, so we can say:

ΔK = Kf = $\frac{1}{2} *m*vf^{2}$ (1)

As ΔK = -ΔU ⇒ ΔK = 352 J (2)

From (1) and (2) we can solve for vf, as follows:

$vf = \sqrt{\frac{2*352J}{40.8kg}} = 4.15 m/s$

So, when the swing passes through its lowest position, Betty moves at 4.15 m/s.

5 0

4 years ago

An object is suspended by a string from the ceiling of an elevator. If the tension in the string is equal to 25 N at an instant

Phantasy [73]

By Newton's second law, the net force on the object is

∑ F = T - mg = - ma

where

• T = 25 N, the tension in the string

• m is the mass of the object

• g = 9.8 m/s², the acceleration due to gravity

• a = 2.0 m/s², the acceleration of the elevator-object system

Solve for m :

25 N - m (9.8 m/s²) = - m (2.0 m/s²)

==> m = (25 N) / (9.8 m/s² - 2.0 m/s²) ≈ 3.2 kg

4 0

3 years ago