The potential energy of a 30N ball on the ground will be zero. With respect to height, h. Potential energy will be calculated like this. P=mgh. So if its on the ground relatively speaking the h=0. Thus inputting into the above formula. P=0.
Answer:
Option C. 30 m
Explanation:
From the graph given in the question above,
At t = 1 s,
The displacement of the car is 10 m
At t = 4 s
The displacement of the car is 40 m
Thus, we can simply calculate the displacement of the car between t = 1 and t = 4 by calculating the difference in the displacement at the various time. This is illustrated below:
Displacement at t = 1 s (d1) = 10 m
Displacement at t= 4 s (d2) = 40
Displacement between t = 1 and t = 4 (ΔD) =?
ΔD = d2 – d1
ΔD = 40 – 10
ΔD = 30 m.
Therefore, the displacement of the car between t = 1 and t = 4 is 30 m.
Answer:
A decrease in the distance between the earth and the moon.
Answer:
429 m
Explanation:
In this exercise you are suppose to simulate a right triangle, the catheti are the distance you walked and the height of the empire state building.
tan(88) = (height) /(distance you walked)
28.64 = height / 15
height = 429 m
Answer:
λ = 8.716 mm
Explanation:
Given:
- d = 10 cm
- Q >= 5 degrees
Find:
- Find the shortest wavelength of light for which this apparatus is useful
Solution:
- The formula that relates the split difference and angle of separation between successive fringes is given by:
d*sin(Q) = n*λ
Where,
λ: wavelength
d: split separation
Q: angle of separation between successive fringes
m: order number.
- Since this apparatus only shows the first order light so m =1
- the shortest possible wavelength corresponds to:
d*sin(Q) = λ
λ = 0.1*sin(5)
λ = 8.716 mm
