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skelet666 [1.2K]
3 years ago
13

Moving a spring toy up and down will create what kind of wave?

Physics
2 answers:
Leya [2.2K]3 years ago
6 0
Yes it’s a transverse wave because the acceleration or movement
tia_tia [17]3 years ago
4 0
I’m not a 100% sure but I believe the transverse wave
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Which type of employee would most likely spend the majority of work time in a vehicle? O a Corrections Officer at a jail O a Dis
dsp73

Answer:

Paramedic

Explanation:

They will be on the move the whole time

8 0
3 years ago
Read 2 more answers
A vertical spring withk= 245N/m oscillates with an amplitude of 19.2cm when 0.457kg hangs from it. The mass posses through the e
Makovka662 [10]

Answer:

 y = -19.2 sin (23.15t) cm

Explanation:

The spring mass system is an oscillatory movement that is described by the equation

      y = yo cos (wt + φ)

Let's look for the terms of this equation the amplitude I

     y₀ = 19.2 cm

Angular velocity is

     w = √ (k / m)

     w = √ (245 / 0.457

     w = 23.15 rad / s

The φ phase is determined for the initial condition   t = 0 s ,  the velocity is negative v (0) = -vo

The speed of the equation is obtained by the derivative with respect to time

     v = dy / dt

     v = - y₀ w sin (wt + φ)

For t = 0

     -vo = -yo w sin φ

The angular and linear velocity are related v = w r

      v₀ = w r₀

      v₀ = v₀ sinφ

      sinφ = 1

      φ = sin⁻¹ 1

      φ = π / 4    rad

Let's build the equation

      y = 19.2 cos (23.15 t + π/ 4)

Let's use the trigonometric ratio π/ 4 = 90º

      Cos (a +90) = cos a cos90 - sin a sin sin 90 = 0 - sin a

       y = -19.2 sin (23.15t) cm

8 0
3 years ago
Suppose that placing 0.3 inch of lead in front of a gamma source reduces the count rate from 1045 cps to 573 cps. What is um^-1
Ainat [17]

Answer:

14.49 g/cm²

Explanation:

I = Io e^-(ux)

Where:

I = 573

Io = 1045

x = 0.3 inches and

rho = 11.4g/cm^3

Using the conversion constant

1 inch = 2.54 cm;

0.3 inches = 0.3 * 2.54 cm

0.3 inches = 0.762 cm

I/Io = e^-(ux), or say

Io/I = e^(ux), taking the In of both sides

ln(Io/I) = ux, making u subject of formula

u = 1/x * ln(Io/I)

u = 1/0.762 * ln(1045/573)

u = 1.312 * 0.6

u = 0.787

Next, we say that

u/rho = 0.7872/11.4 = 0.069

And finally, we make

1/(u/rho) to be our final answer

Inverse of the answer is = 14.49 g/cm²

Therefore, the um^-1 in g/cm^2? is 14.49

5 0
2 years ago
Carbon dioxide (CO2) gas in a piston-cylinder assembly undergoes three processes in series that begin and end at the same state
topjm [15]

Answer:

a) W =400 kJ

b) W = 0 kJ

c) W =-160.944 KJ

Explanation:

<u>Given  </u>

<u><em>Process 1 ---> 2 </em></u>

The relation of the process P = constant

Pressure of point (1) P1 =  10 bar = P2

Volume of point (1) V1   = 1 m^3

Volume of point (2) V2 =4 m^3

The relation of the process V = constant  

<u>Process 2 ---> 3 </u>

The relation of the process V = constant

V3 = V2

Pressure of point (3) P3 = 10 bar

Volume of point (3) V3 = 4 m^3

<u>Process 3 ---> 1 </u>

The relation of the process PV = constant  

<u>Required  </u>

Sketch the processes on the PV coordinates

The work for each process in kJ  

<u>Solution  </u>

The work is defined by  

W=\int\limits^a_b {x} \, dx

<em>a=V2</em>

<em>b=V1</em>

<em>x=P</em>

<em>dx=dV</em>

<u>Process 1 ---> 2  </u>

P3 = P4 = 5 bar  

W=\int\limits^a_b {x} \, dx

<em>a=V3</em>

<em>b=V2</em>

<em>x=4</em>

<em>dx=dV</em>

putting the value of a, b, x, dx in above integral

W=400 kJ

<u>Process 2 ---> 3 </u>

V = constant Then there is no change in the volume,hence W = 0 kJ  

<u>Process 3 ---> 1  </u>

By substituting with point (1) --> 5 x .2 = C ---> C = 1 P = 5V^-1  

 W=\int\limits^a_b {x} \, dx

a=V1

b=V3

x=1V^-1

dx=dV

putting the value of a, b, x, dx in above integral

W=| ln V | limit a and b

  = -160.944 KJ

5 0
3 years ago
What would be the current going through a 200 ohm resister that is connected across a 120 v power supply?
gavmur [86]
Here is your answer

hope it help you

6 0
3 years ago
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