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jenyasd209 [6]
3 years ago
11

The value -2 is a lower bound for the zeros of the function shown below f(x)=4x^3-12x^2-x+15

Mathematics
1 answer:
NISA [10]3 years ago
6 0

We are given

The value -2 is a lower bound for the zeros of the function shown below f(x)=4x^3-12x^2-x+15

So, firstly, we will find value of f(x) at x=-2

we will plug x=-2 into f(x)

we get

f(x)=4x^3-12x^2-x+15

we will plug x=-2

f(-2)=4(-2)^3-12(-2)^2-(-2)+15

now, we can simplify it

f(-2)=-32-12\cdot \:4-\left(-2\right)+15

f(-2)=-63

so,

f(-2)=-63

we know that any zeros always lies between positive and negative value

Here , we got f(-3)=-63 ...which is negative value

so, this is lower bound

Hence , this is TRUE

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