Answer:
There is a 99.99998% probability that at least one valve opens.
Step-by-step explanation:
For each valve there are only two possible outcomes. Either it opens on demand, or it does not. This means that we use the binomial probability distribution to solve this problem.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

In which
is the number of different combinatios of x objects from a set of n elements, given by the following formula.

And p is the probability of X happening.
In this problem we have that:

Calculate P(at least one valve opens).
This is 
Either no valves open, or at least one does. The sum of the probabilities of these events is decimal 1. So:


So


Finally

There is a 99.99998% probability that at least one valve opens.
You would use the function root(Xsub2-Xsub1)^2+(Ysub2-Ysub1)^2.
Now plug in your numbers.
This gives you root(7-1)^2+(5-(-3))^2.
Simplify to root(6)^2+(8)^2. Simplify again to root36+64.
Simplify one more time to root 100. now solve.
Your answer is 10.
Answer:
80
Step-by-step explanation:
You plug in 1200 for x.
C(1200)=0.05(1200) +20
Then solve. Multiply first then add.
60+20
80
Answer:
its b
Step-by-step explanation:
hope this helps