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Free_Kalibri [48]

3 years ago

9

At what the pressure, in atmospheres, that O2, gas at 75°C has a density of 2.00 g/L

1 answer:

kari74 [83]3 years ago

8 0

Pink and fluffy and squishy mangos

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Name for the compound Ag2S

tankabanditka [31]

The name for the compound Ag2S is Silver sulfide.

<u>Explanation</u>:

The name for the compound Ag2S is Silver sulfide. It is the inorganic compound with the formula Ag 2S. A dense black solid, which is used as a photosensitizer in photography.

Silver sulfide is insoluble in most solvents but is degraded using robust acids where the bonds have a low ionic of approximately 10%.

It has a molar mass of 247.80 g / mol. The look is the grayish-black crystal, odorless, soluble in aqueous HCN, aqueous citric acid with KNO3 and insoluble in acids, alkalies.

7 0

2 years ago

Why is the time series useful as a management tool?

katrin [286]

Answer:

A)

Explanation:

It estimates the probability of extinction.

8 0

2 years ago

A compound contains only carbon, hydrogen, nitrogen, and oxygen. Combustion of 0.157g of the compound produced 0.213g of CO2 and

vladimir2022 [97]

Answer:

$C_{7} H_{5}N_{3}O_{6}$

Explanation:

First reaction gives you the number of moles or the mass from Carbon and hydrogen

for carbon:

$0,213gCO_{2} .\frac{1molCO_{2}}{44gCO_{2}} .\frac{1molC}{1molCO_{2}} =0.005molC$

$0.213gCO_{2} .\frac{1molCO_{2}}{44gCO_{2}} .\frac{1molC}{1molCO_{2}} .\frac{12gC}{1molC} = 0.058gC\\$

Analogously for hydrogen:

0.0310g $H_{2}O$ have 0.0034gH or 0.0034mol of H

In the second reaction you can obtain the amount of nitrogen as a percentage and find the mass of N in the first sample.

$0.023gNH_{3} .\frac{1molNH_{3}}{17gNH_{3}} .\frac{1molN}{1molNH_{3}} .\frac{14gN}{1molN} \frac{100}{0.103gsample} =18.4%N$

now

$\frac{18.4gN}{100gsample} .0.157gsample=0.0289gN in the first reaction$

this is equivalet to 0.002mol of N

with this information you can find the mass of oxygen by matter conservation.

$gO=total mass-(gN+gC+gH)=0.157-(0.0289+0.058+0.0034)=0.0666gO$

this is equivalent to 0.004molO

finally you divide all moles obtained between the smaller number of mole (this is mol of H)

$C\frac{0.0048}{0.0034} H\frac{0.0034}{0.0034} N\frac{0.002}{0.0034} O\frac{0.004}{0.0034} =C_{1.4} HN_{0.6} O_{1.2}$

and you can multiply by 5 to obtain: $C_{7} H_{5}N_{3}O_{6}$

4 0

3 years ago

In a solution, the parts of the solution are mixed A) chemically. B) physically. C) only in water. D) by electronic means.

alisha [4.7K]

B. physically i hope this helps

6 0

2 years ago

Read 2 more answers

Please help do not understand!!!!!!!!!!!!!!!

makvit [3.9K]

Answer:

If your asking how much the reactions weigh separately than it should be 25

Explanation:

25 +25=50

7 0

2 years ago