We will use the expression for freezing point depression ∆Tf
∆Tf = i Kf m
Since we know that the freezing point of water is 0 degree Celsius, temperature change ∆Tf is
∆Tf = 0C - (-3°C) = 3°C
and the van't Hoff Factor i is approximately equal to 2 since one molecule of KCl in aqueous solution will produce one K+ ion and one Cl- ion:
KCl → K+ + Cl-
Therefore, the molality m of the solution can be calculated as
3 = 2 * 1.86 * m
m = 3 / (2 * 1.86)
m = 0.80 molal
First find the oxidation states of the various atoms:
<span>in Cr2O2 2- Cr @ +1; In NH3 N @ +3; in CrO3 Cr @ +3, N2 N @ 0 </span>
<span>Note that N gained electrons, ie, was reduced; Cr was oxidized </span>
<span>Now there is a problem, because B has NH4+ which the problem did not, and is not balanced, showing e- in/out </span>
<span>B.NH4+ → N2 </span>
<span>Which of the following is an oxidation half-reaction? </span>
<span>A.Sn 2+ →Sn 4+ + 2e- </span>
<span>Sn lost electrons so it got oxidized</span>
3 elements are present in HCOOH - hydrogen, oxygen, and carbon.
Answer:
The equilibrium will shift left.
Explanation:
Hope this helps <3
Answer:
Carnitine Synthesis
Explanation:
Ascorbic acid acts as a cofactor in various hydroxylation and amidation reactions by electron transfer to enzymes that provide reducing equivalents. Accordingly, ascorbic acid is required or facilitates the conversion of certain proline and lysine residues of the procollagen, the oxidation of lysine side chains to proteins, providing hydroxytrimethylsiline for carnitine synthesis. This means that ascorbic acid is essential for the carnitine synthesis.
Carnitine is derived from amino acids and acts as a cofactor for the enzyme acetyltransferase responsible for the transport of fatty acids to mitochondria. Your presence in the body is very important for feeling energetic and strong. The lack of canitine, influenced by the lack of ascorbic acid in individuals suffering from scurvy, causes a lack of energy.
