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Blababa [14]
3 years ago
8

3. The density, d of an x-box 1 can be found by using the following formula d = m, where mis

Chemistry
1 answer:
scoundrel [369]3 years ago
4 0

Answer:

d = 10490 kg/m³

Explanation:

Density:

Density is equal to the mass of substance divided by its volume.

Units:

SI unit of density is Kg/m3.

Other units are given below,

g/cm3, g/mL , kg/L

Formula:

D=m/v

D= density

m=mass

V=volume

Symbol:

The symbol used for density is called rho. It is represented by ρ. However letter D can also be used to represent the density.

Given data:

Mass of box = 73430 Kg

Volume = 7 m³

density of box = ?

Solution:

d = m/v

d = 73430 Kg/7 m³

d = 10490 kg/m³

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3 years ago
What is the oxidation number of chlorine in HClO4?
Elza [17]

CIO4-=-1

CI=4O=-1

O has a 2- oxidation change so

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8 0
3 years ago
A saturated solution of baso4 has a concentration of 0.5mol/l. a 55ml sample is taken by you. what is the mass of baso4 in the s
SIZIF [17.4K]

Answer:

6.4 g BaSO₄

Explanation:

You have been given the molarity and the volume of the solution. To find the mass of the solution, you need to (1) find the moles BaSO₄ (via the molarity ratio) and then (2) convert moles BaSO₄ to grams BaSO₄ (via the molar mass). It is important to arrange the conversions in a way that allows for the cancellation of units (the desired unit should be in the numerator). The final answer should have 2 sig figs to reflect the sig figs of the given values.

Molarity (mol/L) = moles / volume (L)

(Step 1)

55 mL / 1,000 = 0.055 L

Molarity = moles / volume                             <----- Molarity ratio

0.5 (mol/L) = moles / 0.055 L                        <----- Insert values

0.0275 = moles                                             <----- Multiply both sides by 0.055

(Step 2)

Molar Mass (BaSO₄): 137.33 g/mol + 32.065 g/mol + 4(15.998 g/mol)

Molar Mass (BaSO₄): 233.387 g/mol

0.0275 moles BaSO₄          233.387 g
---------------------------------  x  -------------------  =  6.4 g BaSO₄
                                                1 mole

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2 years ago
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Limiting reactant in this experiment would be Magnesium since it will run out first
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3 years ago
The diagram below shows a box with
Delicious77 [7]
The answer is: D the box will NOT move or change. Hope this helps!
5 0
3 years ago
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