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s2008m [1.1K]
3 years ago
14

Combustion _____.

Chemistry
2 answers:
Otrada [13]3 years ago
4 0
B is your correct anwser
KIM [24]3 years ago
3 0
In combustion energy is released so it is an exothermic process !!

the answer is 2nd one !!
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A balloon at 25°C has 30 L. What will the balloon's volume at 35°C?
anygoal [31]

The balloon's volume at 35°C : V₂=31.01 L

<h3>Further explanation</h3>

Given

T₁ = 25°C+273 = 298 K

V₁ = 30 L

T₂ = 35 °C + 273 = 308 K

Required

The new volume (V₂)

Solution

Charles's Law  

When the gas pressure is kept constant, the gas volume is proportional to the temperature  

\tt \dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}

Input the value :

V₂=(V₁.T₂)/T₁

V₂=(30 x 308)/298

V₂=31.01 L

8 0
3 years ago
A compound is made up of at least
solmaris [256]
Two or more different elements
5 0
3 years ago
What indicators of a chemical reaction occurred in the following equation?
ch4aika [34]

Answer:

1) evolution of gas

2) evolution of heat

Explanation:

In this reaction, glucose is broken down into its constituents; carbon dioxide and water. The question is to decipher indicators of a chemical reaction from the equation.

If we look at the equation carefully, we will notice that a gas was evolved (CO2). The evolution of a gas indicates that a chemical reaction must have taken place. Secondly, energy is given off as heat. This is another indication that a chemical reaction has taken place.

6 0
3 years ago
What is a rechargeable battery?
aleksklad [387]

Answer:

a group of electrochemical cells that can be recharged

6 0
3 years ago
How many grams of ethylene glycol (c2h6o2) must be added to 1.00 kg of water to produce a solution that freezes at -5.00oc? (kf
leonid [27]

Answer: 167 g


Explanation:


1) The depression of the freezing point of a solution is a colligative property ruled by this equation:


ΔTf = i × m × Kf


Where:


ΔTf is the decrease of the freezing point of the solvent due to the presence of the solute.


i is the Van't Hoof factor and is equal to the number of ions per each mole of solute. It is only valid for ionic compounds. Here the solute is not ionice, so you take i = 1


Kf is the molal freezing constant and is different for each solvent. For water it is 1.86 m/°C


2) Calculate the molality (m) of the solution


ΔTf = i × m × Kf ⇒ m = ΔTf / ( i × Kf) = 5.00°C / 1.86°C/m = 2.69 m


3) Calculate the number of moles from the molality definition


m = moles of solute / kg of solvent ⇒ moles of solute = m × kg of solvent


moles of solute = 2.69 m × 1.00 kg = 2.69 moles


4) Convert moles to grams using the molar mass


molar mass of C₂H₆O₂ = 62.07 g/mol


mass in grams = number of moles × molar mass = 2.69 moles × 62.07 g/mol = 166.97 g ≈ 167 g

6 0
3 years ago
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