If fluorine gas (F₂) occupies a volume of 45.5 L at a pressure of 850
1 answer:
Taking into account about the ideal gas law, the mass of fluorine gas is 63.2244 grams.
<h3>What is ideal gas law</h3>An ideal gas is a theoretical gas that is considered to be composed of randomly moving point particles that do not interact with each other. Gases in general are ideal when they are at high temperatures and low pressures.
The pressure, P, the temperature, T, and the volume, V, of an ideal gas, are related by a simple formula called the ideal gas law:
P×V = n×R×T
where:
- P is the gas pressure.
- V is the volume that occupies.
- T is its temperature. The universal constant of ideal gases R has the same value for all gaseous substances.
- R is the ideal gas constant.
- n is the number of moles of the gas.
The molar mass of substance is a property defined as its mass per unit quantity of substance, in other words, molar mass is the amount of mass that a substance contains in one mole.
<h3>Mass of fluorine gas</h3>In this case, you know:
- P= 850 mmHg= 1.11842 atm (being 1 mmHg= 0.00131579 atm)
- V= 45.5 L
- T =100 °C= 373 K (being 0°C= 273 K)
- R= 0.082
- n= ?
Replacing in the ideal gas law:
1.11842 atm ×45.5 L = n×0.082 × 373 K
Solving:
n= (1.11842 atm ×45.5 L)÷ (0.082 × 373 K)
<u><em>n= 1.6638 moles</em></u>
The molar mass of F₂ is 38 g/mole. Then you can apply the folowing rule of three: If by definition of molar mass 1 mole of the compound contains 38 grams, 1.6638 moles of the compound contains how much mass?
<u><em>mass= 63.2244 grams</em></u>
Finally, the mass of fluorine gas is 63.2244 grams.
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La aspirina se prepara haciendo reaccionar ácido salicílico con exceso de anhídrido etanoico. En un experimento, 50.05 g de ácido salicílico se convirtieron en 55.45 g de aspirina. ¿Cuál fue el porcentaje de rendimiento?
<em>In English:</em>
Aspirin is prepared by reacting salicylic acid with excess ethanoic anhydride. In one experiment, 50.05 g of salicylic acid was converted to 55.45 g of aspirin. What was the yield percentage?
Answer:
el rendimiento porcentual para la cantidad dada de ácido salicílico es 84.99 %
<em>In English:</em>
<em>the percent yield for the given amount of salicylic acid is </em><em>84.99%</em>
<em></em>
Explanation:
La ecuación química equilibrada para la reacción se puede escribir como:
C₇H₆O₃ + C₄H₆O₃ → C₉H₈O₄ + HC₂H₃O₂
Para la reacción mostrada arriba; El reactivo limitante de la reacción es el ácido salicílico. Ahora; calcular el porcentaje de rendimiento; se espera que primero determinemos el rendimiento teórico de la reacción.
Entonces; la fórmula para calcular el porcentaje de rendimiento:
El rendimiento teórico se determina de la siguiente manera:
50.05 g * 1 mol / 138.21 g / mol de C₇H₆O₃ * 1 mol de C₉H₈O₄ / 1 mol de C₇H₆O₃ * 180.157 g / mol de C₉H₈O₄ = 65.24 g de C₉H₈O₄
Porcentaje de rendimiento
Porcentaje de rendimiento = 84.99%
Por lo tanto, el porcentaje de rendimiento para la cantidad dada de ácido salicílico es 84.99%
<em>In English:</em>
<em>The balanced chemical eqaution for the reaction can be written as:</em>
<em>C₇H₆O₃ + C₄H₆O₃ → C₉H₈O₄ + HC₂H₃O₂</em>
<em>For the reaction shown above; The limiting reactant from the reaction is salicylic acid. Now; to calculate the percentage yield ; we are expected to first determine the theoretical yield of the reaction. </em>
<em>So; the formula for calculating the percentage yield </em><em> </em>
<em />
<em>The theoretical yield is determined as follows:</em>
<em>50.05 g * 1 mol/ 138.21 g/mol of C₇H₆O₃ * 1 mol of C₉H₈O₄/ 1 mol of C₇H₆O₃ * 180.157 g/mol of C₉H₈O₄ = 65.24 g of C₉H₈O₄ is produced</em>
<em />
<em>Percentage yield </em><em />
<em>Percentage yield = 84.99%</em>
<em />
<em>Thus, the percent yield for the given amount of salicylic acid is </em><em>84.99%</em>
Answer:- atoms.
Solution:- We have been given the grams of carbon tetrachloride and asked to calculate the number of atoms of chlorine. It is a three step conversion problem. In the first we convert the grams of carbon tetrachloride to moles of it. In second step we convert moles of carbon tetrachloride to moles of chlorine and in the third step we convert the moles of chlorine to atoms of chlorine.
For grams to mole conversion we need the molar mass of the compound. Molar mass of carbon tetrachloride is 153.82 grams per mol. If we look at the formula of carbon tetrachloride then four chlorine are present in it. It means 1 mol of carbon tetrachloride has four moles of chlorine. The calculations are as follows:
= atoms
So, there are atoms in 12.2 grams of
.