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nataly862011 [7]
3 years ago
13

What is the advantage of seeds that can be spread over a wide area?

Chemistry
1 answer:
Tema [17]3 years ago
6 0

Answer:

I'm fairly sure it's D

Explanation:

If they're more spread out than they're roots in theory should have more space. Sorry if I'm wrong

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What principle do we use in writing the formula of an ionic compound such as NaCl or MgI2? How do we know that two iodide ions a
Savatey [412]

Answer:

We know based on the charges of each ion and the fact that they must always sum to 0

Explanation:

Na only has one outer electon to give so it is always +1

Mg has two outer electrons so it always gets +2

Halogens have one "missing" electron in their outer shell so they get a -1

For NaCl  (+1) + (-1) = 0

For MgI2 (+2) + 2(-1) = 0

6 0
3 years ago
How did buddhism spread to china?​
Mrac [35]

Answer:

It is widely believed that Buddhism entered China via the Silk Road under the Han Dynasty. After trade and travel was established with the Yuezhi, who by that time were forced southward toward India, Yuezhi monks began to travel with the merchant caravans; preaching their religion along the Silk Road.

Explanation:

i got this from google

4 0
3 years ago
The activation barrier for the hydrolysis of sucrose into glucose and fructose is 108 kJ/mol. Part A If an enzyme increases the
emmasim [6.3K]

Answer:

The barrier has to be 34.23 kJ/mol lower when the sucrose is in the active site of the enzyme

Explanation:

From the given information:

The activation barrier for the hydrolysis of sucrose into glucose and fructose is 108 kJ/mol.

In this  same concentration for the glucose and fructose; the reaction rate can be calculated by the rate factor which can be illustrated from the Arrhenius equation;

Rate factor in the absence of catalyst:

k_1= A*e^{^{^{ \dfrac {- Ea_1}{RT}}

Rate factor in the presence of catalyst:

k_2= A*e^{^{^{ \dfrac {- Ea_2}{RT}}

Assuming the catalyzed reaction and the uncatalyzed reaction are  taking place at the same temperature :

Then;

the ratio of the rate factors can be expressed as:

\dfrac{k_2}{k_1}={  \dfrac {e^{ \dfrac {- Ea_2}{RT} }} { e^{ \dfrac {- Ea_1}{RT} }}

\dfrac{k_2}{k_1}={  \dfrac {e^{[  Ea_1 - Ea_2 ] }}{RT} }}

Thus;

Ea_1-Ea_2 = RT In \dfrac{k_2}{k_1}

Let say the assumed temperature = 25° C

= (25+ 273)K

= 298 K

Then ;

Ea_1-Ea_2 = 8.314 \  J/mol/K * 298 \ K *  In (10^6)

Ea_1-Ea_2 = 34228.92 \ J/mol

\mathbf{Ea_1-Ea_2 = 34.23 \ kJ/mol}

The barrier has to be 34.23 kJ/mol lower when the sucrose is in the active site of the enzyme

8 0
3 years ago
How many moles are in 35.0 grams of H₂O?
Nikitich [7]
1.94 moles


I did 35/18.02 because 18.02 is the molar mass of water
3 0
3 years ago
Any one know the answer?
quester [9]
The last one, answer is D
8 0
3 years ago
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