Ask question

Ask question

All categories

4 years ago

15

In a particular application involving airflow over a surface, the boundary layer temperature distribution may be approximated as

T−Ts/T[infinity]−Ts=1−exp⁡(−Pr(u[infinity]y)/????) Where y is the distance normal to the surface and the Prandtl number, Pr=cpμ/k=0.7, is a dimensionless fluid property. If T[infinity]=400K, Ts=300K, and u[infinity]/υ=5000 m-1, what is the surface heat flux? 6.11

1 answer:

Anni [7]4 years ago

8 0

Answer:

The Surface heat flux is -9205 W/m^2

Explanation:

Explanation is in the following attachment

You might be interested in

Please helppppppppp!!!!!!!!!!?

Alja [10]

Answer:

<h3><em><u>Magnesium has an atomic number of 12, which means its neutral atom has 12 electrons. The Mg2+ ion is formed when the neutral magnesium atom loses 2 electrons, which brings its total number of electrons to 10</u></em></h3>

4 0

3 years ago

A typical rechargeable deep-cycle battery for an electric trolling motor (fishing boat) delivers 10A of current at a voltage of

Oksi-84 [34.3K]

Answer:

a) 360 kQ

b) 4.32 MJ

c) 1200 W-h

Explanation:

a) The definition of the current is.

$I= \frac{Q}{t}$

having a count that 10 hours = 36.000 s

$Q = I*t$

$Q = 36000*10 = 360.000 [Q]$

b) The definition of the Energy in power terms is.

$E = \int\limits^{t}_{0} {P} \, dt$

and the definition of power is:

$P = V*I = 12 * 10 = 120 [W]$

replacing in the energy formula.

$E = \int\limits^{36.000}_{0} {120} \, dt$

solving the integral, have into account that t is in seconds.

$E=P*t=120*36000=4.320.000=4.32 [MJ]$

c) The energy in W-h, we can find it multiplying power by hours

$E = P*t =120*10 = 1200 W-h$ .

3 0

3 years ago

Photons of infrared radiation with wavelengths longer than those of visible light will have what kind of energy compared to that

densk [106]

Answer:

Infrared photons carry lower radiation energy than the visible light.

Explanation:

Each photon carries an energy that is directly proportional to its frequency, being this proportionality constant the Planck's constant h.
So, we can write the energy of a single photon as follows:

$E = h*\nu (1)$

Since there exists an inverse relationship between wavelength and frequency, and infrared radiation has longer wavelengths, this means that its frequency is lower than the one of the visible light.
So, an infrared photon carries less energy that one of the visible light.

6 0

3 years ago

I AM TIMED !! 30 POINTS Which is the smallest possible particle of an element?

zimovet [89]

Answer:

atoms

Explanation:

they are the smallest

4 0

3 years ago

Read 2 more answers

A current of 16.0 mA is maintained in a single circular loop of 1.90 m circumference. A magnetic field of 0.790 T is directed pa

AVprozaik [17]

To solve this problem it is necessary to take into account the concepts related to the magnetic moment and the torque applied over magnetic moments.

For the case of the magnetic moment of a loop we have to,

$\mu = IA$

Where

I = Current

A = Area of the loop

Moreover the torque exerted by the magnetic field is defined as,

$\tau = IAB$

Where,

I = Current

A = Area of the loop

B = Magnetic Field

PART A) First we need to find the perimeter, then

$P = 2\pi r$

$r = \frac{P}{2\pi}$

$r = \frac{1.9}{2\pi}$

$r = 0.3025m,$

The total Area of the loop would be given as,

$A = \pi r^2$

$A = \pi 0.3025^2$

$A = 0.287m^2$

Substituting at the equation of magnetic moment we have

$\mu = (16*10^{-3})(0.287)$

$\mu = 4.58*10^{-3} A.m^2$

Therefore the magnetic moment of the loop is $4.58*10^{-3}Am^2$

PART B) Replacing our values at the equation of torque we have that

$\tau = IAB$

$\tau = (16*10^{-3})(0.287)(0.790)$

$\tau = 3.62*10^{-3}Nm$

Therefore the torque exerted by the magnetic field is $3.62*10^{-3}Nm$

6 0

3 years ago