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olasank [31]
3 years ago
10

Which of earths layers is made up of liquid metal

Physics
2 answers:
alexdok [17]3 years ago
7 0
It’s the outer core!
just olya [345]3 years ago
4 0
The mantle. It is also the largest earth layer, making up about 84% of the earth. 
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Blood cell : Eukaryotic cell
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3 years ago
What is Newton’s second law of motion
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"<em>F = dP/dt. </em> The net force acting on an object is equal to the rate at which its momentum changes."

These days, we break up "the rate at which momentum changes" into its units, and then re-combine them in a slightly different way.  So the way WE express and use the 2nd law of motion is

"<em>F = m·A.</em>  The net force on an object is equal to the product of the object's mass and its acceleration."

The two statements say exactly the same thing. You can take either one and work out the other one from it, just by working with the units.

8 0
3 years ago
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A boy of mass 40kg eats bananas contains of 980 joule. If this energy is used to lift him up from ground,the height to which he
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Answer:

h = 2.49 [m]

Explanation:

In order to solve this problem we must use the definition of potential energy, which tells us that energy is equal to the product of mass by gravity by height.

The potential energy can be calculated by means of this equation:

Ep = m*g*h

where:

Ep = potential energy = 980 [J]

m = mass = 40 [kg]

g = gravity acceleration = 9.81 [m/s^2]

h = elevation [m]

Now replacing:

980 = 40*9.81*h

h = 2.49 [m]

7 0
3 years ago
A student makes a model of the sun-Earth system by swinging a ball around her head. Using this model, the student is trying to e
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c. gravitational attraction between the sun and earth

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What percentage of the takeoff velocity did the plane gain when it reached the midpoint of the runway? a plane accelerates from
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When is at the end of the runway the velocity of the plane is given by the equation vf^{2}=0+2*a*s    where s=1800 m is the runway length. Thus
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vf =134.164 (m/s)  

At half runway the velocity of the plane is
v^{2}=2*5* \frac{1800}{2}=9000 ( \frac{m}{s} )^{2}&#10; 
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Therefore at midpoint of runway the percentage of takeoff velocity is
‰P= \frac{v}{vf}=  \frac{94.87}{134.164}=0.707
6 0
3 years ago
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