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3 years ago

Which of earths layers is made up of liquid metal

Physics

2 answers:

alexdok [17]3 years ago

7 0

It’s the outer core!

just olya [345]3 years ago

4 0

The mantle. It is also the largest earth layer, making up about 84% of the earth.

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balandron [24]

You have to get points to asked a question and then you can help people to get points and it you want to have friends send them inventions but it you don't have no points you can't asked quenstions

8 0

3 years ago

Read 2 more answers

A particle with charge −− 5.90 nCnC is moving in a uniform magnetic field B⃗ =−(B→=−( 1.28 TT )k^k^. The magnetic force on the p

maks197457 [2]

Answer:

Explanation:

Given that,

Charge q=-5.90nC

Magnetic field B= -1.28T k

And the magnetic force

F =−( 3.70×10−7N )i+( 7.60×10−7N )j

Let the velocity be V(xi + yj + zk)

Then, the force is given as

Note i×i=j×j×k×k=0

i×j=k. j×i=-k

j×k=i. k×j=-i

k×i=j. i×k=-j

The force in a magnetic field is given as

F= q(v×B)

−( 3.70×10−7N )i+( 7.60×10−7N )j =

q(xi + yj + zk) × -1.28k

−( 3.70×10−7N )i+( 7.60×10−7N )j=

q( -1.28x i×k - 1.28y j×k - 1.28z k×k)

−( 3.70×10−7N )i+( 7.60×10−7N )j=

q( 1.28xj - 1.28y i )

−( 3.70×10−7N )i+( 7.60×10−7N )j=

q( -1.28y i + 1.28x j)

So comparing comparing coefficients

let compare x axis component

-( 3.70×10−7N )i=-1.28qy i

−3.70×10−7N = -1.28qy

y= -3.7×10^-7/-1.28q

y= -3.7×10^-7/-1.28×-5.90×10^-9)

y=-48.99m/s

y≈-49m/s

Let compare y-axisaxis

7.6×10−7N j = 1.28qx j

7.6×10−7N = 1.28qx

x= 7.6×10^-7/1.28q

x= 7.6×10^-7/1.28×-5.90×10^-9

x=-100.64m/s

a. Then, the velocity of the x component is x= -100.64m/s

b. Also, the velocity component of the y axis is y=-49m/s

c. We will compute

V•F

V=-100.64i -49j

F=−( 3.70×10−7 N )i+( 7.60×10−7 N )j

Note

i.j=j.i=0. Also i.i = j.j =1

V•F is

(-100.64i-49j)•−(3.70×10−7N)i+(7.60×10−7 N )j =

3.724×10^-5 - 3.724×10^-5=0

V•F=0

d. Angle between V and F

V•F=|V||F|Cosx

0=|V||F|Cosx

Cosx=0

x= arccos(0)

x=90°

Since the dot product is zero, from vectors , if the dot product of two vectors is zero, then the vectors are perpendicular to each other

4 0

3 years ago

What is the acceleration of an object with a mass of 15 kg and a coefficient of friction of 0.18

11111nata11111 [884]

Answer:

a = 1.764m/s^2

Explanation:

By Newton's second law, the net force is F = ma.

The equation for friction is F(k) = F(n) * μ.

In this case, the normal force is simply F(n) = mg due to no other external forces being specified

F(n) = mg = 15kg * 9.8 m/s^2 = 147N.

F(k) = F(n) * μ = 147N * 0.18 = 26.46N.

Assuming the object is on a horizontal surface, the force due to gravity and the normal force will cancel each other out, leaving our net force as only the frictional one.

Thus, F(net) = F(k) = ma

26.46N = 15kg * a

a = 1.764m/s^2

7 0

3 years ago

Two forces act on a 41-kg object. One force has magnitude 65 N directed 59° clockwise from the positive x-axis, and the other ha

Genrish500 [490]

Answer:

a = 1.41 m/s²

Explanation:

Given that

mass ,m= 41 kg

F₁ = 65 N , θ = 59°

F₂ = 35 N ,θ = 32°

The component of Force F₁

F₁x= F₁cos59° i

F₁x= 65 x cos59° i = 33.47 i

F₁y= - F₁ sin 59° j

F₁y= - 65 x sin 59° j = - 55.71 j

The component of Force F₂

F₂x= F₂ sin 32° i

F₂x= 35 x sin 32° i = 18.54 i

F₂y= F₂ cos 32° j

F₂y= 35 x cos 32° j = 29.68 j

The total force F

F= 33.47 i + 18.54 i - 55.71 j + 29.68 j

F= 52.01 i - 26.03 j

The magnitude of the force F

$F=\sqrt{52.01^2+26.03 ^2}\ N$

F=58.16 N

We know that

F= m a

a= Acceleration

m=mass

58.16 = 41 x a

a = 1.41 m/s²

6 0

4 years ago

Water at the top of Horseshoe Falls (part of Niagara Falls) is moving horizontally at 9.2 m/s as it goes off the edge and plunge

dangina [55]

Water at the top of Horseshoe Falls (part of Niagara Falls) is moving horizontally at 9.2 m/s, the angle with respect to the vertical is mathematically given as

$\theta=15.93$

<h3>What angle with respect to the vertical is the falling water moving as it enters the pool?</h3>

Generally, the equation for velocity is mathematically given as

V^2=u^2+2as

Therefore

V^{2}=0+2(9.81)(53)

V=32.2m/s

In conclusion, The angle

$\theta =tan^{-1}\frac{(9.20m/s)}{(32.23m/s)}$

$\theta=15.93$