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Liono4ka [1.6K]
3 years ago
15

A television of mass 13 kg sits on a shelf. What is the normal force acting on the television?

Physics
2 answers:
Mnenie [13.5K]3 years ago
4 0

13 \times 9.8 = 127.4
B is the correct answer
Alisiya [41]3 years ago
4 0

Answer:

Normal force, F = 127 N

Explanation:

It is given that,

Mass of the television, m = 13 kg

It is sitting on the shelf. We have to find the normal force acting on it. The forces acting on it are normal force and its weight. So, the normal force is given by :

F = mg

g = acceleration due to gravity

N=13\ kg\times 9.8\ m/s^2

F = 127.4 Newton

or

F = 127 N

Hence, the normal force acting on the television is 127 N

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A 12 kg box is at rest on your kitchen counter, which your cat is pawing at with a horizontal force of 40 N. If the coefficient
murzikaleks [220]

Answer; I think it's False.

8 0
3 years ago
Q.Solve the following circuit find total resistance RT. Also find value of voltage across resister RC.
vagabundo [1.1K]

Answer:

R_total = 14.57 Ω ,  V_C = 1.176 V

Explanation:

To solve this circuit we are going to find the equivalent resistance of each branch, let's remember

* Serial resistance  

         R_{eq} = ∑ R_{i}

* For resistance in parallel

        1 / R_{eq} = ∑ 1/R_{i}

We solve the two branches of the wheatstone bridge

Series resistors

Branch B

         R_B = Rb + R4

         R_B = 2 + 18

         R_B = 20 Ω

Branch C

         R_C5 = Rc + R5

         R_C5 = 3 + 12

         R_C5 = 15 Ω

Resistance in parallel R_B and R_C5

         1 / R_BC = 1 / R_B + 1 / R_C5

          1 / R_BC = 1/20 + 1/15 = 0.116666

          R_BC = 8.57 Ω

Now we have a single branch, we solve the series resistance

          R_total = R_A + R_BC

          R_total = 6 + 8.57

          R_total = 14.57 Ω

b) they ask us for the voltage in the resistance R_C

Let's remember that the voltage in a series circuit is the sum of the voltages

           10 = V_a + V_BC

           10 = i R_a + i R_BC = i (R_a + R_BC)

           i = 10 / (R_a + R_BC)

           i = 10 / (14.57)

           i = 0.6863 A

The current in the series circuit is constant

          V_BC = i R_BC

          V_BC = 0.6863 8.57

          V_BC = 5.8819 V

This voltage is divided in the bridge, for the two branches in parallel it is the same, but the resistance is different in each branch.

     Branch C

             V_BC = i R_C5

             i = V_BC / R_C5

             i = 5.8819 / 15

             i = 0.39213 A

In this branch we have two resistors in series, let's remember that the current in a series circuit is constant

             V_C = i R_C

              V_C = 0.39213 3

              V_C = 1.176 V

3 0
3 years ago
State how you agree or disagree with the following statement. A good circuit cannot have internal resistance.​
Rashid [163]

Answer: I do

Explanation:

Resistance opposes current thereby reducing the amount of current that flows through a circuit. In other words, it leads to a loss of electrical energy.

Ideally speaking, a good circuit should have no internal resistance as this would lead to more energy having to be supplied to overcome that resistance. External resistance however, is not a bad thing. For instance, oxygen being removed from lightbulbs.

7 0
3 years ago
Calculate the change in length of a Pyrex glass dish (Coefficient of linear expansion for Pyrex is 3 x 10^-6 /C) that is 0.3 met
Readme [11.4K]

Answer:

0.000225 m

Explanation:

Coefficient of linear expansion = \alpha_L=3\times 10^{-6} /C

Length = 0.3 meters

ΔT = Change in temperature = 250 °C

Linear expansion

\frac{\Delta L}{L} = \alpha_L\Delta T\\\Rightarrow \Delta L=\alpha_L\Delta T\times L\\\Rightarrow \Delta L=3\times 10^{-6}\times 0.3\times 250=0.000225\ m

Change in length of the Pyrex glass dish is 0.000225 m.

3 0
3 years ago
an athlete in a hammer-throw event swings a 7.0-kilogram hammer in a horizontal circle at a constant speed of 12 meters per seco
Semenov [28]

Answer:

ac = 72 m/s²

Fc = 504 N

Explanation:

We can find the centripetal acceleration of the hammer by using the following formula:

a_c = \frac{v^2}{r}

where,

ac = centripetal acceleration = ?

v = constant speed = 12 m/s

r = radius = 2 m

Therefore,

a_c = \frac{(12\ m/s)^2}{2\ m}

<u>ac = 72 m/s²</u>

<u></u>

Now, the centripetal force applied by the athlete on the hammer will be:

F_c = ma_c\\F_c = (7\ kg)(72\ m/s^2)

<u>Fc = 504 N</u>

6 0
2 years ago
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