Question

What is the kinetic energy of the ball just before it hits the ground?

Answer 1

Answer:

$0.5mv^{2}$

Explanation:

Kinetic energy, $KE= 0.5mv^{2}$

while potential energy, PE= mgh where m is the mass, v is the velocity of the ball, g is acceleration due to gravity and h is the height.

The question requires kinetic energy hence we use the $KE= 0.5mv^{2}$

Since the figures are not given, we maintain that $KE= 0.5mv^{2}$