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sergey [27]
3 years ago
6

The field of a solenoid is most like the field of a: long, straight wire single bar magnet horseshoe magnet single pole

Physics
2 answers:
dimulka [17.4K]3 years ago
8 0

Answer:

Single bar magnet

Explanation:

As we know that magnetic field of solenoid inside the solenoid is strong and given by formula

B = \frac{\mu_0 N i}{L}

here we know

L = length of solenoid

i = current in the coil

now as we observe the field outside the solenoid the magnetic field will start decreasing as we go far away from the end.

so strength of magnetic field will be more near the end and start decreasing as we move away from it

this all characteristics are similar to the magnetic field of a bar magnet

so this solenoid is similar to a bar magnet

user100 [1]3 years ago
4 0
The outside magnetic field of a solenoid is similar to that of a bar magnet even though the inside field is strong and uniform.
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Four children pull on the same stuffed toy at the same time yet there is no net force on the toy. How is this possible.
Stels [109]

Answer:

Net force is Zero.

Explanation:

If all forces that are equal and opposite are exerted on an object the resulting force will be Zero.

3 0
3 years ago
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A centrifuge in a medical research laboratory rotates at an angular speed of 3,650 rev/min. When switched off, it rotates 46.0 t
erma4kov [3.2K]

Answer:

The constant angular acceleration of the centrifuge = -252.84 rad/s²

Explanation:

We will be using the equations of motion for this calculation.

Although, the parameters of this equation of motion will be composed of the angular form of the normal parameters.

First of, we write the given parameters.

w₀ = initial angular velocity = 2πf₀

f₀ = 3650 rev/min = (3650/60) rev/s = 60.83 rev/s

w₀ = 2πf₀ = 2π × 60.83 = 382.38 rad/s

θ = 46 revs = 46 × 2π = 289.14 rad

w = final angular velocity = 0 rad/s (since the centrifuge come rest at the end)

α = ?

Just like v² = u² + 2ay

w² = w₀² + 2αθ

0 = 382.38² + [2α × (289.14)]

578.29α = -146,214.4644

α = (-146,214.4644/578.29)

α = - 252.84 rad/s²

Hope this Helps!!!

6 0
3 years ago
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Extend your thinking: household appliances are usually connected in a parallel circuit. why do you think it might be a problem i
alexandr1967 [171]
The equivalent resistance of several devices connected in parallel is given by
\frac{1}{R_{eq}} =  \frac{1}{R_1}+ \frac{1}{R_2}+...+ \frac{1}{R_n}
where R_i are the resistances of the various devices. We can see that every time we add a new device in parallel, the term \frac{1}{R_{eq}} increases, therefore the equivalent resistance of the circuit R_{eq} decreases.

But Ohm's law:
I= \frac{V}{R_{eq}}
tells us that if the equivalent resistance decreases, the total current in the circuit increases. The power dissipated through the circuit (and so, the heat produced) depends on the square of the current:
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3 years ago
Imagine you are holding an apple. how could you increase the potential energy of this apple?
Ray Of Light [21]

If you're holding the apple at your waist, lift it to your mouth.
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Since energy is conserved ... it never magically appears or
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3 years ago
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Explanation:

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3 years ago
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