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sergey [27]
3 years ago
6

The field of a solenoid is most like the field of a: long, straight wire single bar magnet horseshoe magnet single pole

Physics
2 answers:
dimulka [17.4K]3 years ago
8 0

Answer:

Single bar magnet

Explanation:

As we know that magnetic field of solenoid inside the solenoid is strong and given by formula

B = \frac{\mu_0 N i}{L}

here we know

L = length of solenoid

i = current in the coil

now as we observe the field outside the solenoid the magnetic field will start decreasing as we go far away from the end.

so strength of magnetic field will be more near the end and start decreasing as we move away from it

this all characteristics are similar to the magnetic field of a bar magnet

so this solenoid is similar to a bar magnet

user100 [1]3 years ago
4 0
The outside magnetic field of a solenoid is similar to that of a bar magnet even though the inside field is strong and uniform.
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Determined to test the law of gravity for himself, a student walks off a skyscraper 180 m high, stopwatch in hand, and starts hi
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a)  v₀ = - 164.62 m / s , c) y = 122.5 m

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We can solve this exercise using the free fall kinematic relations.

We put our reference system on the floor, so the height of the skyscraper is y₀ = 180m and the floor level is y = 0 m

 

For the boy

         y = y₀ + v₀ t - ½ g t²

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        y = ½ g t2

For superman

        y = y₀ + v₀ (t-5) - ½ g (t-5)²

how superman grabs the lot just before hitting the ground

we look for the time it takes the boy down

         t = √ (2 y₀ / g)

         t = √ (2 180 / 9,8)

         t = 6.06 s

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         v₀ (t-5) = -y₀ + ½ g (t-5)²

         v₀ (6.06 -5) = -180 + ½ 9.8 (6.06 -5)²

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the negative sign indicates that the initial speed is down

b) to graph the position of the two we use the table

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    0             180                 180

   1              175.1               180

   5              57.5              180

   6                3.6                10.18

see attachment for the two curves

c) calculate the height that falls a lot in the 5 seconds (t = 5)

           y = -1/2 g t²

           y = ½ 9.8 5²

           y = 122.5 m

for this height superman has not yet left the skyscraper, so the boy hits the ground

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