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arsen [322]
3 years ago
13

Which type of bond has an electronegativity difference greater than 1.7? a. ionic c. nonpolar covalent b. metallic d. polar cova

lent
Physics
1 answer:
cestrela7 [59]3 years ago
8 0

Answer: Option (a) is the correct answer.

Explanation:

An ionic bond is formed by transfer of electrons between the two chemically combining atoms. Whereas a covalent bond is defined as the bond formed by sharing of electrons between the two chemically combining atoms.

When electronegativity difference is from 0.0 to 0.4 then bond formed between the two atoms is non-polar covalent in nature.

When electronegativity difference is greater than 0.4 and less than 1.7 then bond between the two atoms is a polar covalent bond.

When electronegativity difference is 1.7 or greater than the bond formed is ionic in nature.

Thus, we can conclude that ionic type of bond has an electronegativity difference greater than 1.7.

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Answer:

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3 years ago
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Answer:

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Kinetic energy (K) is the energy associated with bodies that are in motion, depends on the mass and speed of the body and is calculated using the formula:

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K=kinetic energy (J)

m =mass of the body (kg)

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for this problem We replace in the equation (1)

me=9.1*10^{-31} kg = electron mass

ve=1.5*10^{8} \frac{m}{s}=Half the speed of light

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We replace in  the  equation (1) :

Ke=\frac{1}{2}*me*ve^{2}

Ke=\frac{1}{2} *9.1*10^{-31} *(1.5*10^{8} )^{2}

Ke=4.55*10^{-31} *(1.5)^{2} *(10^{8} )^{2}

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Answer:

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