We are given the mass of an <span>aluminum sculpture which is 145 kg and a horizontal force equal to 668 Newtons. The coefficient of friction can be determined by dividing the horizontal force by the weight of the object. In this case, 668 N / 145 * 9.8 equal to coeff of friction of 0.47</span>
Answer:
Refractive index of a medium = Speed of light in vacuum/Speed of light in a medium
1.5 = 3 x 108 / Speed of light in medium
Speed of light in the medium = 3 x 108 /1.5
= 2 x 108 m/s.
Explanation:
Answer:
1.33
Explanation:
speed of light in vacuum, c = 3 x 10^8 m/s
speed of light in medium, v = 2.26 x 10^8 m/s
The refractive index of the medium is given by
μ = speed of light in vacuum / speed of light in medium
μ = (3 x 10^8) / (2.26 x 10^8)
μ = 1.33
Answer:
Continuous
Explanation:
A circuit can only light up a lightbulb if there is a continuous path for electricity to travel from one end of the energy source to the other end.
