Heya!!!
Answer to your question:
C.
Energy transferred to a machine equals energy transferred from it.
Law of conservation of energy states that total energy of an isolated system remains constant
Energy can neither be created nor be destroyed. Machine follows the same rule.
Hope it helps ^_^
Answer:
The heat gain of the room due to higher efficiency is 2.84 kW.
Explanation:
Given that,
Output power of shaft = 75 hp
Efficiency = 91%
High efficiency = 95.4%
We need to calculate the electric input given to motor
Using formula of efficiency
We need to calculate the electric input
For, heigh efficiency
The reduction of the heat gain of the room due to higher efficiency is
Put the value into the formula
Hence, The heat gain of the room due to higher efficiency is 2.84 kW.
(105 N/m) x (0.1 m) = <em>10.5 Newtons</em>.
Answer:
27 m/s²
Explanation:
Traveling in uniform circular motion will cause a centripetal acceleration, an acceleration towards the center of the circle.
The acceleration of an object in circular motion is defined as a = v²/r.
Let's set the radius to be 5 m, since it is always unchanging. Solving for the velocity using a = 3 m/s² and r = 3 m gives us:
The velocity is 3 m/s when the acceleration is 3 m/s² and the radius of the circular path is 3 m.
Now let's triple the velocity: 3 m/s → 9 m/s.
Let's solve for the acceleration using v = 9 m/s and r = 3 m.
- a = (9)²/3
- a = 81/3
- a = 27
The acceleration is 27 m/s² if you triple your speed.
This makes sense because a is directly proportional to v², meaning that if you triple your speed, you increase the acceleration a by a factor of 3², which is a 9 times increase.
As a sidenote, doubling your speed would increase the acceleration by a factor of 2² - a 4 times increase.
The distance traveled while accelerating from rest is
D = 1/2 a t² .
For this problem, we shall totally ignore air resistance.
We do so completely without any reservation or guilt,
because we know that there is no air on the moon.
D = (1/2) · (1.6 m/s²) · (9 sec)²
= (0.8 m/s²) · (81 s²)
= (0.8 · 81) m
= 64.8 meters .
(That's about 213 feet ! The astronaut must have dropped the feather
from his spacecraft while he was aloft ... either just before touchdown
or just after liftoff.)
