Expenses including those for linen service, ice, and paper goods might fluctuate depending on demand. Other variables are constants. No change occurs to it. This is further explained below.

<h3>What is Susie's operation?</h3>

Generally, Fixed expenditures, in contrast to the more unpredictable variable costs like advertising, happen regularly at the same time each year regardless of fluctuations in revenue or other variables. It doesn't get the performance bus.

Here, we are given with table.

$\begin{tabular}{|c|c|c|}Other Expenses & Variable Expense & Fixed Expense. \\ Linen rental & $X$ & \\ piano rental & & $X$ \\ ice & $X$ & $X$ \\insurance & & $X$ \\ Pension plan & & $X$ \\Snow shoveling dees cparkinglot) & & \\Paper products & $X$ & $X$ \\ Kituen equipment & & $X$ \\ lease (mixer) & & \\Longterm debt. & & \\ Realestate tax. & & \\\end{tabular}$

In conclusion,

Linen rental, ice, and Paper Products are Variable expenses because it is based on requirement
Others are fixed by other factors. it's not affected

Read more about Expenses

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7 0

2 years ago

A loaded ore car has a mass of 950 kg and rolls on rails with negligible friction. It starts from rest and is pulled up a mine s

Ierofanga [76]

Answer:

a). P=11.04kW

b). Pmax=11.38 kW

c). Wt=6423.166kJ

Explanation:

The power of the motor when the speed is constant is the work in a determinate time.

$P=\frac{W}{t}$

The work is the force the is applicated in a distance so

W=F*d

replacing:

$P=F*\frac{d}{t}$ and $\frac{d}{t}$ determinate distance in time is velocity so

a).

$P=F*v$

$F=m*a\\F=m*g*sin(33.5)$

$P=950kg*9.8\frac{m}{s^{2}}*sin(33.5)*2.15\frac{m}{s}\\P=11047.846 W\\P=11.0478 kW$

b).

The maximum power must the motor provide, is the maximum force with the maximum speed of the motor in this case

The first step is find the acceleration so

$vi=0\frac{m}{s} \\vf=2.15 \frac{m}{s}\\vf=vi+a*t\\vf-vi=a*t\\ a=\frac{vf-vi}{t}= a=\frac{2.15\frac{m}{s}-0\frac{m}{s}}{13s}\\a=0.1653 \frac{m}{s^{2}}$

The maximum force is when the car is accelerating so

$Ft=Fa+Fg\\Ft=m*a+m*g*sin(33.5)\\Ft=950kg*0.1653\frac{m}{s^{2}}+950*9.8\frac{m}{s^{2}}*sin(33.5)\\Ft=5295.565 N$

so the maximum force is the maximum force by the maximum speed

$Pmax=Ft*v\\Pmax=5295.565N*2.15\frac{m}{s}\\Pmax=11385.46\\Pmax=11.3854kW$

c).

The total energy transfer without any friction is the weight move in the high axis y in this case, so is easy to know that distance

W=m*g*h

h=Length*sin(33.5)

W=m*g*Length*sin(33.5)

W=950 kg*9.8* 1250m*sin(33.5)

W=6423166.667 kJ

W=6423.166 kJ

4 0

4 years ago

The average energy of the atoms that make up a substance which is changing from a liquid to a solid is

nirvana33 [79]

decreasing

I hope it help c:

7 0

3 years ago

A hammer taps on the end of a 4.0-m-long metal bar at room temperature. A microphone at the other end of the bar picks up two pu

Mashcka [7]

Answer: c*m on now

Explanation:

u dumb b***h

6 0

4 years ago