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sammy [17]
4 years ago
14

A periodic transverse wave has an amplitude of 0.20 meter and a wavelength of 3.0 meters. If the frequency of this wave is 12 Hz

, what is its speed?
Physics
1 answer:
Aleksandr [31]4 years ago
7 0

The speed is 36 m/s

<u>Explanation:</u>

Speed of any wave is the measure of how fast the wave is propagating or travelling in medium. So, the speed of the wave can be calculated as the product of frequency with wavelength of that wave.

Thus, speed is directly proportional to the frequency and wavelength of a wave.

Speed = Frequency \times wavelength

<u>Given data:</u>

frequency of the wave is given as 12 Hz

wavelength is given as 3 m

Therefore, the speed will be

Speed = 12 × 3 = 36 m/s

Thus, the speed of the transverse wave is 36 m/s.

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A block of mass 0.404 0.404 kg is hung from a vertical spring and allowed to reach equilibrium at rest. As a result, the spring
VARVARA [1.3K]

To solve this problem it is necessary to apply the concepts related to the Force from Hook's law as well as the definition of the period provided by the same definition.

We know that the Force can be defined as

F = xk \rightarrow mg = kx \Rightarrow k = \frac{mg}{x}

Where

k = Spring constant

x = Displacement

g = Gravity

m = mass

At the same time the period of a spring mass system is defined as

T = 2\pi \sqrt{\frac{m}{k}}

Where

m = Mass

k = Spring constant

Our values are given as,

m = 0.404kg

x = 0.666m

Replacing to find the value of the Spring constant we have that

k = \frac{mg}{x}

k = \frac{(0.404)(9.8)}{0.666}

k = 5.944N/m

Now using the formula of the period we know that

T = 2\pi \sqrt{\frac{m}{k}}

T = 2\pi \sqrt{\frac{0.404}{5.944}}

T = 1.638s

Finally, if the oscillation was 0.359m

The maximum height will be determined by the total length of that oscillation being equivalent to

h=2a

h = 2*0.359

h = 0.718m

4 0
3 years ago
Compare the weight of a mountain climber when she is at the bottom of a mountain with her weight when she is at the top of the m
kakasveta [241]

Answer:

The correct answer is  a. Both are the same

Explanation:

For this calculation we must use the gravitational attraction equation

    F = G m M / r²

Where M will use the mass of the Earth, m the mass of the girl and r is the distance of the girl to the center of the earth that we consider spherical

To better visualize things, let's repair the equation a little

     F = m (G M / r²)

The amount in parentheses called acceleration of gravity, entered the force called peos

     g = G M / r²

     F = W

    W = m g

When analyzing this equation we see that the variation in the weight of the girl depends on the distance, which is the radius of the earth plus the height where the girl is

    r = Re + h

    Re = 6.37 10⁶ m

    r² = (Re + h)²

    r² = Re² (1 + h / Re)²

Let's replace

    W = m (GM / Re²)   (1+ h / Re)⁻²

    W = m g   (1+ h / Re)⁻²

This is the exact expression for weight change with height, but let's look at its values ​​for some reasonable heights h = 6300 m (very high mountain)

     h / Re = 10 ⁻³

     (1+ h / Re)⁻² = 0.999⁻²

Therefore, the negligible weight reduction, therefore, for practical purposes the weight does not change with the height of the mountain on Earth

The correct answer is a

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3 years ago
A.
UNO [17]
Calculate the minimum speed record at the point B in order for the real question to reach the top
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A 6.0-kg ball is sliding to the right at 25.0m/s and strikes a second ball (15-kg) that is initially at rest head-on. After the
katrin [286]

Answer:

15 m/s to the right

Explanation:

Let's say right is positive and left is negative.

Momentum is conserved:

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

(6.0 kg) (25.0 m/s) + (15 kg) (0 m/s) = (6.0 kg) (-12.5 m/s) + (15 kg) v₂

v₂ = 15 m/s

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Which tennis tournament is considered the Grand Daddy of them all?
joja [24]

Answer:

Wimbledon

Explanation:

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3 years ago
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