To solve this problem it is necessary to apply the concepts related to the Force from Hook's law as well as the definition of the period provided by the same definition.
We know that the Force can be defined as

Where
k = Spring constant
x = Displacement
g = Gravity
m = mass
At the same time the period of a spring mass system is defined as

Where
m = Mass
k = Spring constant
Our values are given as,
m = 0.404kg
x = 0.666m
Replacing to find the value of the Spring constant we have that



Now using the formula of the period we know that



Finally, if the oscillation was 0.359m
The maximum height will be determined by the total length of that oscillation being equivalent to



Answer:
The correct answer is a. Both are the same
Explanation:
For this calculation we must use the gravitational attraction equation
F = G m M / r²
Where M will use the mass of the Earth, m the mass of the girl and r is the distance of the girl to the center of the earth that we consider spherical
To better visualize things, let's repair the equation a little
F = m (G M / r²)
The amount in parentheses called acceleration of gravity, entered the force called peos
g = G M / r²
F = W
W = m g
When analyzing this equation we see that the variation in the weight of the girl depends on the distance, which is the radius of the earth plus the height where the girl is
r = Re + h
Re = 6.37 10⁶ m
r² = (Re + h)²
r² = Re² (1 + h / Re)²
Let's replace
W = m (GM / Re²) (1+ h / Re)⁻²
W = m g (1+ h / Re)⁻²
This is the exact expression for weight change with height, but let's look at its values for some reasonable heights h = 6300 m (very high mountain)
h / Re = 10
⁻³
(1+ h / Re)⁻² = 0.999⁻²
Therefore, the negligible weight reduction, therefore, for practical purposes the weight does not change with the height of the mountain on Earth
The correct answer is a
Calculate the minimum speed record at the point B in order for the real question to reach the top
Answer:
15 m/s to the right
Explanation:
Let's say right is positive and left is negative.
Momentum is conserved:
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
(6.0 kg) (25.0 m/s) + (15 kg) (0 m/s) = (6.0 kg) (-12.5 m/s) + (15 kg) v₂
v₂ = 15 m/s