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spayn [35]
3 years ago
12

There is an increasing demand for berries in Paul’s town. He wants to cultivate berries to earn profits. To do so, he wants to c

heck whether the soil in his farm is suitable for cultivating berries. Which characteristic of soil will most accurately check the suitability of land for growing berries?
A) soil profile
B) soil texture
C ) soil horizon
D) soil moisture
Physics
1 answer:
iren [92.7K]3 years ago
8 0

Answer:

Option (B)

Explanation:

Soil texture is defined as the amount of soil that is present and the type of materials that comprises the soil such as sand, silt and clay particles, of which the sands are the coarser particles and the clay is the finer particles.

This soil texture enables us to determine the properties such as moisture content,  porosity and permeability and the number of nutrients that it can provide for the growth and expansion of plants.

Thus, from the above-given condition, the soil texture property helps in checking the suitability of the land for growing berries.

Thus, the correct answer is option (B).

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A 70.0 kg ice hockey goalie, originally at rest, has a 0.110 kg hockey puck slapped at him at a velocity of 31.5 m/s. Suppose th
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Answer

given,

mass of the goalie(m₁) = 70 kg

mass of the puck (m₂)= 0.11 kg

velocity of the puck = 31.5 m/s

elastic collision

v_1=\dfrac{m_2-m_1}{m_1+m_2}v_1+\dfrac{2m_2}{m_1+m_2}v_2

v_{pf}=\dfrac{0.11-70}{0.11+70}31.5+\dfrac{2m_2}{m_1+m_2}\times (0)

v_{pf}=-31.4\ m/s

v'_2 = \dfrac{2m_1v_1}{m_1+m_2}-\dfrac{(m_2-m_1)v_2}{m_2+m_1}

v_{gf} = \dfrac{2\times 0.11\times 31.5}{0.11+70}-\dfrac{(0.11-70)\times 0}{m_1+m_2}

v_{gf} = \dfrac{2\times 0.11\times 31.5}{0.11+70}

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4 0
3 years ago
How long does it take (in minutes) for light to reach venus from the sun, a distance of 1.152 × 108 km?
7nadin3 [17]
Using the precise speed of light in a vacuum (299,792,458 \ \frac{m}{s}), and your given distance of 1.152 * 10^{8} km, we can convert and cancel units to find the answer. The distance in m, using \frac{1000 \ m}{1 \ km}, is 1.152 * 10^{11} m. Next, for the speed of light, we convert from s to min, using \frac{1 \ min}{60 \ s}, so we divide the speed of light by 60. Finally, dividing the distance between the Sun and Venus by the speed of light in km per min, we find that it is 6.405 min.

7 0
3 years ago
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