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juin [17]
3 years ago
11

The chart shows the solubility of different substances.

Chemistry
2 answers:
Annette [7]3 years ago
8 0
Answer: 1) Temperature can change the solubility of a solute.

Explanation:

The chart is missing so there is no way to tell what does the graph show.

Yet, I can help you because I can explain the status of each statement of the choices. As you will see there is only one possibility..

<span>1) Temperature can change the solubility of a solute.

Yes, temperature definetly can, and mostly do, modify the solubility of a solute.

You can search any chart of solubility and will find that.

I can give you two examples:

a) Sodium chloride: dissolve some spoons of salt in a cold water  until you can not dissolve more. Then, heat the water, you will find that more salt will get dissolved, proving that the temperature of the solution increases the solubility of sodium chloride.

b) Carbon dioxide gas: the soft drinks have CO₂ molecules dissolved in it.
 
The higher the temperature of the soft drink the less the amount of CO₂(g) that can be dissolved. That is why the soda bottling plants cool the beverage before adding the CO₂(g).

2) </span><span>Temperature has no affect on the solubility of a solute.

Since this is the opposite to the first statement and the first is true, this is false.

3) Salt has a greater solubility than sugar.

False.

This is an empirical result, which you cannot predict theoretically. So you need to see at the data either in a table or in a chart. Else you can test it at home. After the empirical data are shown it results that more grams of sugar can be dissolved in water compared to salt.

That is something you ca see in a chart or you can prove by yourself.

4) Nitrite salt has a greater solubility than sugar. </span>

False.

Looking at some data you can find that sodium nitrite solutiliby is aroun  70 - 100 g/10 g while sugar (sucrose) solutiblity is around 180 - 235 g/ 100 g.

Gnoma [55]3 years ago
4 0

Answer:

Temperature can change the solubility of a solute

Explanation:

i know this because i am big brained

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A compound has a molar mass of 86.0 g/mol and an empirical formula of C3H7 what is the molecular formula
zmey [24]
The formula for the molecular formula is molar mass/ empirical formula

So, the empirical formula of C3H7 is equal to C*3 + H*7 which is equal to 12*3 +  7. Then use the molecular formula = 86 / (12*3+7) = 2

Therefore, the molecular formula is 2 times the empirical formula which is C6H14.
3 0
3 years ago
Analysis of an athletes urine found the presence of a compound with a molar mass of 312 g/mol. How many moles of this compound a
rewona [7]
<h3>Answer:</h3>

= 5.79 × 10^19 molecules

<h3>Explanation:</h3>

The molar mass of the compound is 312 g/mol

Mass of the compound is 30.0 mg equivalent to 0.030 g (1 g = 1000 mg)

We are required to calculate the number of molecules present

We will use the following steps;

<h3>Step 1: Calculate the number of moles of the compound </h3>

Moles=\frac{mass}{molar mass}

Therefore;

Moles of the compound will be;

=\frac{0.030}{312g/mol}

      = 9.615 × 10⁻5 mole

<h3>Step 2: Calculate the number of molecules present </h3>

Using the Avogadro's constant, 6.022 × 10^23

1 mole of a compound contains 6.022 × 10^23  molecules

Therefore;

9.615 × 10⁻5 moles of the compound will have ;

= 9.615 × 10⁻5 moles × 6.022 × 10^23  molecules

= 5.79 × 10^19 molecules

Therefore the compound contains 5.79 × 10^19 molecules

5 0
3 years ago
Can you name these for me
Mashcka [7]

Answer:

1. E. mitochondrion

2. C. chloroplasts

3. G. vacuole

4. A. cell membrane

5. B. cell wall

6. D.cytoplasm

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8. cytoplasm

9. cell membrane

10. chloroplast

11. mitochondrion

12. nucleus

13. cell wall

14. vacuole

Explanation:

- Be familiar which each term.

- Look up diagram to understand image.

- Hope that helped! Please let me know if you need further explanation on each word.

4 0
3 years ago
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QveST [7]

Answer:

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Explanation:

8 0
1 year ago
How many moles of c2h6o are in a 24.5 gram sample?
andreev551 [17]
0.5326086957 moles ....
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