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natita [175]
2 years ago
12

REALLY NEED HELP!!! Chemistry

Chemistry
1 answer:
kicyunya [14]2 years ago
3 0

Answer:

C.) 2

Explanation:

The pH equation is:

pH = -log[H⁺]

In this equation, [H⁺] is the molarity of the acid. In this case, the acid is HCl. Molarity can be found using the equation:

Molarity (M) = moles / volume (L)

Since you were given moles and volume, you can find the molarity of HCl.

Molarity = moles / volume

Molarity = 0.01 moles / 1.00 L

Molarity = 0.01 M

Now, you can plug the molarity of the acid into the pH equation.

pH = -log[H⁺]

pH = -log[0.01]

pH = 2

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The equilibrium constant Kc for the reaction PCl3(g) + Cl2(g) ⇌ PCl5(g) is 49 at 230°C. If 0.70 mol of PCl3 is added to 0.70 mol
Ymorist [56]

Answer : The correct option is, (B) 0.11 M

Solution :

First we have to calculate the concentration PCl_3 and Cl_2.

\text{Concentration of }PCl_3=\frac{\text{Moles of }PCl_3}{\text{Volume of solution}}

\text{Concentration of }PCl_3=\frac{0.70moles}{1.0L}=0.70M

\text{Concentration of }Cl_2=\frac{\text{Moles of }Cl_2}{\text{Volume of solution}}

\text{Concentration of }Cl_2=\frac{0.70moles}{1.0L}=0.70M

The given equilibrium reaction is,

                            PCl_3(g)+Cl_2(g)\rightleftharpoons PCl_5(g)

Initially                 0.70        0.70              0

At equilibrium    (0.70-x)   (0.70-x)           x

The expression of K_c will be,

K_c=\frac{[PCl_5]}{[PCl_3][Cl_2]}

K_c=\frac{(x)}{(0.70-x)\times (0.70-x)}

Now put all the given values in the above expression, we get:

49=\frac{(x)}{(0.70-x)\times (0.70-x)}

By solving the term x, we get

x=0.59\text{ and }0.83

From the values of 'x' we conclude that, x = 0.83 can not more than initial concentration. So, the value of 'x' which is equal to 0.83 is not consider.

Thus, the concentration of PCl_3 at equilibrium = (0.70-x) = (0.70-0.59) = 0.11 M

The concentration of Cl_2 at equilibrium = (0.70-x) = (0.70-0.59) = 0.11 M

The concentration of PCl_5 at equilibrium = x = 0.59 M

Therefore, the concentration of PCl_3 at equilibrium is 0.11 M

3 0
3 years ago
What is the compound name for the ion chemical formula AgBr?
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Answer:

Silver bromide.

Explanation:

4 0
3 years ago
Which statement is true?
algol [13]

The statement that is true is that B. Atoms always remain intact during chemical reactions.

Atoms simply mean the <u>basic units of matter.</u> They're the defining structure of an element. Atom is also known as the smallest unit of matter.

It should be noted that atoms always remain intact during chemical reactions. They cannot be added and removed when there are <em>chemical reactions.</em>

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A solution was prepared by mixing 50.00 ml of 0.100 M of HNO3 and 100.00 ml of 0.200 M HNO3. Calculate the molarity of the final
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Answer:

The molarity of this final solution is 0.167 M

Explanation:

Step 1: Data given

Volume of a 0.100 M HNO3 solution = 50.0 mL

Volume of a 0.200 M HNO3 = 100.0 mL

Step 2: Calculate moles

The final molarity must lie between 0.1M and 0.2M  

Moles = molarity * volume

Moles HNO3 in 50mL of a 0.100M solution = 0.05 L *0.100 M = 0.005 mol

Moles HNO3 in 100mL of a 0.200M solution = 0.100 L*0.200 = 0.020mol

total moles = 0.005+0.020 = 0.025 moles in 150mL solution = 0.150L

Step 3: Calculate molarity of final solution

Molarity = mol / volume

Molarity 0.025 moles /0.150  L

Molarity = 0.167M

The molarity of this final solution is 0.167 M

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A cup has a mixture of iron filings, sand, and salt. How could you separate theses 3 materials? Write out the procedures you wou
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Explanation:

A cup of mixtures of iron fillings, sand and salt is a mixture who constituents are in the same phase i.e solid.

To separate them out we use the physical properties of the substances.

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