Do you remember when you were learning about the "Least Common
Multiple" of two numbers, and you were wondering why you had to learn
it, because you were so sure that you'd never need to use it ? Do you
remember that ?
Well, HERE's where you get to use it. This question is just looking for
the LCM of 6 and 15 . THAT's how many days it will be before you get
homework in both subjects on the same day again.
(It's not 90 days, and it's not 60 days.)
Answer:
0.512a³ cubic units
Step-by-step explanation:
Given a cube of length, a, then when decreased by 20%, what's left is actually 80% of the original. So, for this case, we have a cube with a length of 80%(a) = 0.80a.
Now, to compute for the volume of a cube, we multiply the length three times to itself. Or, in other words, raise the length to the third power. That means the volume of the new cube is (0.8a)³ = 0.512a³ cubic units.
Answer:
its a rectangle
Step-by-step explanation:
how to explain this
Answer:

Step-by-step explanation:
So, the function, P(t), represents the number of cells after t hours.
This means that the derivative, P'(t), represents the instantaneous rate of change (in cells per hour) at a certain point t.
C)
So, we are given that the quadratic curve of the trend is the function:

To find the <em>instanteous</em> rate of growth at t=5 hours, we must first differentiate the function. So, differentiate with respect to t:
![\frac{d}{dt}[P(t)]=\frac{d}{dt}[6.10t^2-9.28t+16.43]](https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bdt%7D%5BP%28t%29%5D%3D%5Cfrac%7Bd%7D%7Bdt%7D%5B6.10t%5E2-9.28t%2B16.43%5D)
Expand:
![P'(t)=\frac{d}{dt}[6.10t^2]+\frac{d}{dt}[-9.28t]+\frac{d}{dt}[16.43]](https://tex.z-dn.net/?f=P%27%28t%29%3D%5Cfrac%7Bd%7D%7Bdt%7D%5B6.10t%5E2%5D%2B%5Cfrac%7Bd%7D%7Bdt%7D%5B-9.28t%5D%2B%5Cfrac%7Bd%7D%7Bdt%7D%5B16.43%5D)
Move the constant to the front using the constant multiple rule. The derivative of a constant is 0. So:
![P'(t)=6.10\frac{d}{dt}[t^2]-9.28\frac{d}{dt}[t]](https://tex.z-dn.net/?f=P%27%28t%29%3D6.10%5Cfrac%7Bd%7D%7Bdt%7D%5Bt%5E2%5D-9.28%5Cfrac%7Bd%7D%7Bdt%7D%5Bt%5D)
Differentiate. Use the power rule:

Simplify:

So, to find the instantaneous rate of growth at t=5, substitute 5 into our differentiated function:

Multiply:

Subtract:

This tells us that at <em>exactly</em> t=5, the rate of growth is 51.72 cells per hour.
And we're done!