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KATRIN_1 [288]
3 years ago
9

4) A safe contains 120 coins, the value of which is $10. If the coins consist of nickels and dimes, how many of each kind are in

it?
5) A sum of $14 is made of 92 coins, consisting of dimes and quarters.How many are there of each kind of coin?
6) A boy's coins, consisting of nickels and dimes, amount to 42.15. If the number of dimes exceeds 3 times the number of nickels by 4, find the number of each kind of coin?
Mathematics
1 answer:
Sergio [31]3 years ago
3 0
120=x+y and 10=.05x+.10y
120-x=y then subsitute 10=.05x+.10(120-x) distruibte and solve you can do it feel free to go off of my math.
x(nickels) y(dimes)

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Jack is a college athlete who has been weighing himself weekly on the same scale in the athletic center for the past few years.
Radda [10]

Answer:

a) Since the Confidence is 0.90 or 90%, the value of \alpha=0.1 and \alpha/2 =0.05, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.05,0,1)".And we see that z_{\alpha/2}=\pm 1.64

b) \bar X \sim N(\mu ,\frac{\sigma}{\sqrt{n}})

And the standard error is given by:

SE = \frac{\sigma}{\sqrt{n}}=\frac{3}{\sqrt{9}}=1

c) \bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

And the margin of error is:

ME= z_{\alpha/2} \frac{\sigma}{\sqrt{n}} = 1.64

And then the confidence interval is be given by:

200-1.64 = 198.36

200+1.64 = 201.64

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X= 200 represent the sample mean

\mu population mean (variable of interest)

\sigma=3 represent the population standard deviation

n=9 represent the sample size  

Part a

Since the Confidence is 0.90 or 90%, the value of \alpha=0.1 and \alpha/2 =0.05, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.05,0,1)".And we see that z_{\alpha/2}=\pm 1.64

Part b

The distribution for the sample mean is given by:

\bar X \sim N(\mu ,\frac{\sigma}{\sqrt{n}})

And the standard error is given by:

SE = \frac{\sigma}{\sqrt{n}}=\frac{3}{\sqrt{9}}=1

Part c

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

And the margin of error is:

ME= z_{\alpha/2} \frac{\sigma}{\sqrt{n}} = 1.64

And then the confidence interval is be given by:

200-1.64 = 198.36

200+1.64 = 201.64

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3 years ago
Help with cal 2 exercise involving integrals?
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\displaystyle\int\frac{\sqrt{x^2+1}}x\,\mathrm dx=\int\frac{\sqrt{\tan^2B+1}}{\tan B}\sec^2B\,\mathrm dB

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Then

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erastovalidia [21]

Answer:

1. KLP + PLM = 180 degrees (straight line)

2. 3x + angle PLM = 180 degrees

3. angle PLM = 180 - 3x

4. PMN = P + PLM (Exterior angle)

5. 2x + 72 = x + 180 - 3x

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Step-by-step explanation:

1. Notice that angle KLP + angle PLM is a straight line, so KLP + PLM = 180 degrees (straight line)

2. angle KLP = 3x, so

3x + angle PLM = 180 degrees

3. angle PLM = 180 - 3x

4. PMN = P + PLM (Exterior angle)

5. 2x + 72 = x + 180 - 3x

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Can someone please help me with this please!!!!!
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Answer:

a,c,d and e are TRUE.

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