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wolverine [178]
3 years ago
14

PLEASE HELP ME WITH THIS!!!

Mathematics
1 answer:
Digiron [165]3 years ago
7 0

Answer

the first option

Step-by-step explanation:

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Examine the equation.<br><br> –2(–x + 9) = 2(x – 9)<br> 2x – 18 = 2x – 18<br> This equation has
kolezko [41]

Answer:

infinite solutions

Step-by-step explanation:

6 0
3 years ago
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A recent broadcast of a television show had a 10 ​share, meaning that among 6000 monitored households with TV sets in​ use, 10​%
Kisachek [45]

Answer:

Null and alternative hypothesis

H_0: \pi \geq0.25\\\\H_1: \pi

Test statistic z=-26.82

P-value P=0

The null hypothesis is rejected.

It is concluded that the proportion of households tuned into the program is less than 25%. The claim of the advertiser is rigth and got statistical support.

Step-by-step explanation:

We have to perform a hypothesis test of a proportion.

The claim is that less than 25% were tuned into the program, so we will state this null and alternative hypothesis:

H_0: \pi \geq0.25\\\\H_1: \pi

The signifiance level is 0.01.

The sample has a proportion p=0.1 and sample size of n=6000.

The standard deviation of the proportion, needed to calculate the test statistic, is:

\sigma_p=\sqrt{\frac{\pi(1-\pi)}{N} } =\sqrt{\frac{0.25(1-25)}{6000} } =0.0056

The test statistic is calculated as:

z=\frac{p-\pi+0.5/N}{\sigma_p} =\frac{0.1-0.25+0.5/6000}{0.0056}=\frac{-0.1499}{0.0056}  =-26.82

As this is a one-tailed test, the P-value is P(z<-26.82)=0. The P-value is smaller than the significance level (0.01), so the effect is significant.

Since the effect is significant, the null hypothesis is rejected. It is concluded that the proportion of households tuned into the program is less than 25%. The claim of the advertiser is rigth and got statistical support.

3 0
3 years ago
If a person walks 2.4 miles in i.5hours how far can he walk in 3hours
Lubov Fominskaja [6]
I used the cross product method
5x = 2.4 •3
5x=7.2
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8 0
3 years ago
66 cm
galina1969 [7]
Diameter so i’m assuming it’s one :)
5 0
3 years ago
Solve for y please I have no clue I am so lost thank you
Inga [223]

In the Triangle ABD, Using Pythagoras theorem we can write

AB^2=BD^2+AD^2\\ \\ AB^2=9^2+y^2\\ \\ AB^2=81+y^2\\ \\

In the Triangle ACD using Pythagoras Theorem

AC^2=AD^2+CD^2\\ \\ AC^2=y^2+7^2\\ \\ AC^2=y^2+49\\

Now in the larger Triangle ABC, we can write

AB^2+AC^2=BC^2

Now substitute the values from the above equations we get

81+y^2+49+y^2=(9+7)^2\\ \\ 130+2y^2=16^2\\ \\ 130+2y^2=256\\ \\ 65+y^2=128\\ \\ y^2=128-65=63\\ \\ y=\sqrt{63} =3\sqrt{7} \\

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3 years ago
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