Answer:
Force exerted by the hinge on the beam = 109.24N
Explanation:
Weight = mg = 26 x 9.81 = 255.06 N
Vertical component = T sin θ
Horizontal component = Tcos θ
Now, there are 3 vertical forces acting on the beam. These are;
- The downward force which is the weight of the beam.
- The vertical components of the tension in the cable.
-The force that hinge exerts on the beam are the upward forces.
Hence, for the beam to remain horizontal, the sum of the upward forces must be equal to the weight of the beam.
For us to determine the vertical component of the tension in the cable, we will do a torque problem. Let the pivot point be at the hinge. Let’s assume that the length of the beam is L. The vertical component of the tension in the cable will produce clockwise torque while the weight of the beam will produce counter clockwise torque.
Tbus;
Clockwise torque = TL sin 61
Since the center of mass of beam is at the middle of the beam, the distance from the hinge to the weight of the beam is L/2.
Counter clockwise torque = WL/2
Thus;
TL sin 61 = WL/2
L will cancel out.
T sin 61 = 255.06/2
T x 0.8746 = 127.53
T = 127.53/0.8746 = 145.82 N
Now, the equation to determine the vertical component of the force that the hinge exerts on the beam is given as;
T + F = W
Thus;
145.82 + F = 255.06
F = 255.06 - 145.82 = 109.24 N
