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iren [92.7K]
3 years ago
11

What is thE Rquation fo calculating the electrical force between two charges?

Physics
2 answers:
OLEGan [10]3 years ago
8 0

The direction of the electrical force is dependent upon whether the charged objects are charged with like charge or opposite charge and upon their spatial orientation. By knowing the type of charge on the two objects, the direction of the force on either one of them can be determined with a little reasoning.

umka21 [38]3 years ago
4 0

The equation for calculating the electrical force between the two charges is given by Coulomb's law

F=\frac{k q1 q2}{r^{2}}

K=constant= 9 x 10⁹ N m²/C²

q1= charge on first particle

q2= charge on second particle

r= distance between the two charges

Greater is the magnitude of the charges, greater will be the force between the two charges. The force is inversely proportional to the square of the distance between the charges.

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Answer:

The number of turns in the solenoid is 230.

Explanation:

Given that,

Rate of change of current, \dfrac{dI}{dt}=0.0240\ A/s

Induced emf, \epsilon=12.4\ mV=12.4\times 10^{-3}\ V

Current, I = 1.5 A

Magnetic flux, \phi=0.00338\ Wb

The induced emf through the solenoid is given by :

\epsilon=L\dfrac{dI}{dt}

or

L=\dfrac{\epsilon}{(di/dt)}........(1)

The self inductance of the solenoid is given by :

L=\dfrac{N\phi}{I}.........(2)

From equation (1) and (2) we get :

\dfrac{\epsilon}{(di/dt)}=\dfrac{N\phi}{I}

N is the number of turns in the solenoid

N=\dfrac{\epsilon I}{\phi (dI/dt)}

N=\dfrac{12.4\times 10^{-3}\times 1.5}{0.00338 \times 0.024}

N = 229.28 turns

or

N = 230 turns

So, the number of turns in the solenoid is 230. Hence, this is the required solution.

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If an object is 16.76 cm in front of a convex mirror that has a focal length of 67.1 cm, how far behind the mirror will the imag
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a) The magnetic field created by a current-carrying wire is proportional to the current:

B ∝ I, B = magnetic field strength, I = current

The magnetic force acting on a current-carrying wire immersed in a magnetic field is proportional to the current and the magnetic field strength:

F ∝ IB, F = magnetic force, I = current, B = magnetic field strength

Let's focus on wire 1.

Since wire 2's current is doubled, wire 2 produces a magnetic field twice as strong as before.

Wire 1's current is also doubled, therefore we now have a wire having <em>twice as strong a current</em> immersed in <em>twice as strong a magnetic field</em>. The magnetic force on wire 1 (and you can make a similar argument for wire 2) will be four times as strong as before.

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