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3 years ago

10

Pls help‼️Help me with these questions! :/

1 answer:

TiliK225 [7]3 years ago

4 0

Answer:

No number answer; don't want to pull out a calculator lol

Explanation:

Capacitors are added in parallel; opposite of resistors.

So for 9, add 10 and 2.5 then do ((1/12.5)+(1/.3))^-1.

For 10, add 0.75 and 15 first, then the rest is the same idea as 9.

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Using this formula a = F/m What acceleration results from exerting a 125N force on a 0.65kg

Softa [21]

Answer:

Acceleration = 192.3 m/s² (Approx.)

Explanation:

Given:

Force = 125 N

Mass of ball = 0.65 kg

Find:

Acceleration

Computation:

We know that;

Acceleration = Force / Mas

So,

Acceleration = 125 / 0.65

Acceleration = 192.3 m/s² (Approx.)

5 0

3 years ago

Why does immersion oil improve resolution?

Umnica [9.8K]

Answer:

d. It increases numerical aperture and maintains a uniform light speed.

Explanation:

In optical microscopes, various immersion mediums are used to improve or enhance the resolution. Immersion oils like cedar and Leica oils are one of those mediums which are used to improve resolution by increasing the numerical aperture and keeping the speed of light uniform.

7 0

3 years ago

A 180 g model airplane charged to 18 mC and traveling at 2.2 m/s passes within 8.6 cm of a wire, nearly parallel to its path, ca

viva [34]

Answer:

$a=0.2*10^{-5}g$

Explanation:

From the question we are told that:

Mass $M=180=>0.18kg$

Charge $Q=18mC=18*10^-^3C$

Velocity $v=2.2m/s$

Length of Wire $L=8.6cm=>0.086$

Current $I=30A$

Generally the equation for Magnetic Field of Wire B is mathematically given by

$B=\frac{\mu_0*I}{2\pi*l}$

$B=\frac{4*3.14*10^-^7*I}{2*3.14*8.6}$

$B=6.978*10^{-5}T$

Generally the equation for Force on the plane F is mathematically given by

$F=qvB$

Therefore

$ma=qvB$

$a=\frac{qvB}{m}$

$a=\frac{18*10^{-5}83.4*6.978*10^{-5}}{0.18kg}$

$a=2.37*10^{-5}$

Therefore in Terms of g's

$a=\frac{2.37*10^{-5}}{9.8}$

$a=0.2*10^{-5}g$

8 0

2 years ago

A shopper does 157 J of work pushing a cart with 10.9 N force

Tanzania [10]

The cart travelled a distance of 14.4 m

Explanation:

The work done by a force when pushing an object is given by:

$W=Fd cos \theta$

where:

F is the magnitude of the force

d is the displacement

$\theta$ is the angle between the direction of the force and the displacement

In this problem we have:

W = 157 J is the work done on the cart

F = 10.9 N is the magnitude of the force

$\theta=0^{\circ}$ , assuming the force is applied parallel to the motion of the cart

Therefore we can solve for d to find the distance travelled by the cart:

$d=\frac{W}{F cos \theta}=\frac{157}{(10.9)(cos 0)}=14.4 m$

Learn more about work:

brainly.com/question/6763771

brainly.com/question/6443626

#LearnwithBrainly

4 0

3 years ago

Select the correct answer from each drop-down menu.

earnstyle [38]

Answer:

a transverse (sort of a plot of a sine or cosine graph, basically)

b longitudinal

c Electromagnetic (an electric wave and a magnetic wave travelling together at right angles to each other)

Explanation:

7 0

3 years ago