Pcollisin physics :)

A surface is bombarded by particles, each of mass small 'm', which have velocity

ale4655 [162]

Answer:

B. 2nmv

Explanation:

Pressure is force over area.

P = F / A

Force is mass times acceleration.

F = ma

Acceleration is change in velocity over change in time.

a = Δv / Δt

Therefore:

F = m Δv / Δt

P = m Δv / (A Δt)

The total mass is nm.

The change in velocity is Δv = v − (-v) = 2v.

A = 1 and Δt = 1.

Plugging in:

P = (nm) (2v) / (1 × 1)

P = 2nmv

8 0

3 years ago

580 nm light shines on a double slit

lesantik [10]

Answer:

Angular position of the first minimum is 0.27 degree

Explanation:

As we know by the formula of single slit diffraction pattern

$a sin\theta = m\lambda$

here we have

a = d = 0.000125 m

for m = 1

$\lambda = 580 nm$

now we have

$0.000125 sin\theta = 580 \times 10^{-9}$

$sin\theta = 4.64 \times 10^{-3}$

$\theta = 0.27 degree$

6 0

3 years ago

What is the magnitude of the acceleration of a speck of clay on the edge of a potter's wheel turning at 45 rpm (revolutions per

Brilliant_brown [7]

Answer:

$a_{cp}=7.77m/s^2$

Explanation:

The equation for centripetal acceleration is $a_{cp}=\frac{v^2}{r}$ .

We know the wheel turns at 45 rpm, which means 0.75 revolutions per second (dividing by 60), so our frequency is f=0.75Hz, which is the inverse of the period T.

Our velocity is the relation between the distance traveled and the time taken, so is the relation between the circumference $C=2\pi r$ and the period T, then we have: