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3 years ago

5×67=a. (67×10)÷2b. (67x2)+(67×2)c. (6 ×7)×5d.(5×6)+(5×7)

Mathematics

1 answer:

lbvjy [14]3 years ago

4 0

Answer:

a).

= (67×10)÷2

= 670 ÷ 2

= 335

Explanation:

a).

= (67×10)÷2

= 670 ÷ 2

= 335

So, 5×67 = (67×10)÷2

=> 335 = 335

b).

= (67x2)+(67×2)

= 134 × 134

= 268

So, 5×67 ≠ (67x2)+(67×2)

=> 268 ≠ 335

c).

= (6 ×7)×5

= 42 × 5

= 210

So, 5×67 ≠ (6×7)×5

=> 210 ≠ 335

d).

= (5×6)+(5×7)

= 30 + 35

= 65

So, 5×67 ≠ (5×6)+(5×7)

=> 65 ≠ 335

Hence, (a) is the correct answer.

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It is given that $\Sigma x=108$ , $\Sigma y=138$ , $\Sigma x^{2} =1249$ , $\Sigma y^{2} =2280$ and $\Sigma(x y)=1676$

Also, the random sample is $n=10$

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$r=\frac{n\left(\sum x y\right)-\left(\sum x\right)(\Sigma y)}{\sqrt{\left[n \sum x^{2}-\left(\sum x\right)^{2}\right]\left[n \Sigma y^{2}-(\Sigma y)^{2}\right]}}$

Substituting the values in the formula, we have,

$r=\frac{10(1676)-(108)(138)}{\sqrt{\left[10(1249)-(108)^{2}\right]\left[10(2280)-(138)^{2}\right]}}$

Simplifying the values, we get,

$r=\frac{16760-14904}{\sqrt{\left[12490-11664\right]\left[22800-19044\right]}}$

Subtracting the values in both numerator and denominator, we have,

$r=\frac{1856}{\sqrt{\left[826\right]\left[3756\right]}}$

Multiplying the denominator,

$r=\frac{1856}{\sqrt{3102456}}$

Simplifying, we have,

$r=\frac{1856}{1761.4}$

Dividing, we get,

$r=1.054$

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3 years ago

5×67=a. (67×10)÷2b. (67x2)+(67×2)c. (6 ×7)×5d.(5×6)+(5×7)​

5×67=a. (67×10)÷2b. (67x2)+(67×2)c. (6 ×7)×5d.(5×6)+(5×7)