Answer:
(w^2 - 4w + 16)
Step-by-step explanation:
Note that w^3 +64 is the sum of two perfect cubes, which are (w)^3 and (4)^3. The corresponding factors are (w + 4)(w^2 - 4w + 16).
Therefore,
(w^3 +64)/(4+ w) reduces as follows:
(w^3 +64)/(4+ w) (4 + w)(w^2 - 4w + 16)
--------------------------- = --------------------------------- = (w^2 - 4w + 16)
4 + w 4 + w
Answer:
True
Step-by-step explanation:
Why true I had that problem and it was true.
Answer:
The simplest form is 1/r^7 + 1/s^12
Step-by-step explanation:
The given expression is r^-7+s^-12.
Notice that the exponents of both the base are negative
So, we will apply the rule which is:
a^-b = 1/a^b
Which means that to change the exponent into positive we will write it as a fraction:
r^-7+s^-12.
= 1/r^7 + 1/s^12..
Therefore the simplest form is 1/r^7 + 1/s^12....
The answer would be false
Answer:
i belive it is the 3rd on
Step-by-step explanation:
sorry if wrong
