A certain quantity decays exponentially over time. The initial quantity at t = 0 is 25,000. The quantity decays at a rate of 5%.
2 answers:
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6x^4-17x^3-7x^2+13x=3
6x^4-17x^3-7x^2+13x-3=3-3
6x^4-17x^3-7x^2+13x-3=0
y=6x^4-17x^3-7x^2+13x-3
y=0
The solutions are: x=-1, 1/2, 1/3 and 3
6x^4-17x^3-7x^2+13x-3=3-3
6x^4-17x^3-7x^2+13x-3=0
y=6x^4-17x^3-7x^2+13x-3
y=0
The solutions are: x=-1, 1/2, 1/3 and 3
The answer is C.
To solve these types of equations you first need to make sure that you equation is equal to 0. In this case all of the numbers are already on the same side so no work needs to be done there. Then we can get a, b and c values for the quadratic equation by looking at the coefficients.
a = 4 (number attached to x^2)
b = -6 (number attached to x)
c = 1 (number with no variable attached)
Now we can put this into the quadratic equation.
To solve these types of equations you first need to make sure that you equation is equal to 0. In this case all of the numbers are already on the same side so no work needs to be done there. Then we can get a, b and c values for the quadratic equation by looking at the coefficients.
a = 4 (number attached to x^2)
b = -6 (number attached to x)
c = 1 (number with no variable attached)
Now we can put this into the quadratic equation.