Answer:Use an excess of ethane
Explanation:
The halogenation of alkanes is a substitution reaction. All the hydrogen atoms in the alkanes could be potentially substituted. How ever the reaction can be controlled by using an excess of either the alkane or the halogen. If the aim (as it is in this question) is to minimize the yield of halogenated alkanes, an excess of the alkane (in this case, ethane) is used.
Answer:
The configuration of the atom would be 2-8-2.
Explanation:
Any atom of an element combines with other element to complete its octet and become stable.
The electron configuration of the given atom is 2-8-6. That means the atom has 6 electrons in its outermost shell. To become stable the atom should have 8 electrons in its outermost shell. The given atom has 6 electrons so it either lose 6 electrons or gain 2 electrons to complete its octet.
But we know the atom having 5,6,7 electrons in its outermost shell they do not lose, they gain either 3 or 2 or 1 electrons to complete its octet.
So we say that atom with the electron configuration 2-8-6 bond with the atom having electron configuration 2-8-2.
Answer: Option (A) is the correct answer.
Explanation:
Force acting on a dam is as follows.
F =
.......... (1)
Now, when we double the depth then it means H is increasing 2 times and then the above relation will be as follows.
F' = 
F' =
........... (2)
Now, dividing equation (1) by equation (2) as follows.
=
Cancelling the common terms we get the following.
=
4F = F'
Thus, we can conclude that if doubled the depth of the dam the hydrostatic force will be 4F.
Answer:
1. Climate can be described based on a specific event.
2. tells you what types of clothes you should own for a full year
3. air pressure, temperature, humidity, wind speed, and direction are recorded for a specific area
4. cooler climates
5. The higher latitudes are the warmest latitudes
Explanation:
Answer:
a. S = 2.41 x 10⁻⁴ M
Explanation:
The solubility S of a gas in water at a given temperature is given by the equation
S = Kp where S= solubility of the gas
K= Henry's Constant for the gas
p = partial pressure of the gas
solving for S
S = 3.70 x 10⁻⁴ M/atm x 0.650 atm =2.41 x 10⁻⁴ M