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4 years ago

A chemical reaction in which heat is

Chemistry

2 answers:

ollegr [7]4 years ago

7 0

Answer:

b)exothermic reaction

Explanation:

Natalka [10]4 years ago

4 0

Exothermic reaction

I researched it, and it says that it’s Exothermic reaction is the answer.

I sincerely hope this helps you ♥︎

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You need a 30% alcohol solution. On hand, you have a 200 mL of a 10% alcohol mixture. You also have 55% alcohol mixture. How muc

Art [367]

Answer: 160 ml

Explanation:

The expression used will be :

$C_1V_1+C_2V_2=C_3V_3$

where,

$C_1$ = concentration of Ist alcohol solution= 10%

$C_2$ = concentration of 2nd alcohol solution= 55%

$V_1$ = volume of Ist alcohol solution = 200 ml

$V_2$ = volume of 2nd alcohol solution= v ml

$C_3$ = concentration of resulting alcohol solution= 30%

$V_2$ = volume of resulting alcohol solution= (v+200) ml

Now put all the given values in the above law, we get the volume of added.

$(10\times 200)+(55\times v)=(30\times (v+200)ml)$

By solving the terms, we get :

$v=160ml$

Therefore, the volume of 55% mixture needed to be added to obtain the desired solution is 160 ml.

5 0

3 years ago

Write the empirical formula of at least four binary ionic compounds that could be formed from the following ions: Zn2+, Ni4+, F-

hram777 [196]

Ionic compounds are formed between oppositely charged ions.

A binary ionic compound is composed of ions of two different elements - one of which is a positive ion(metal), and the other is negative ion (nonmetal).

To write the empirical formula of binary ionic compound we must remember that one ion should be positive and other ion should be negative, then only the correct formula should be written. To write the empirical formula the charges of opposite ions should be criss-crossed.

First empirical formula of binary ionic compound is written between $Zn^{2+} (Positive ion)and F^{-} (Negative ion)$

First Formula would be $ZnF_{2}$

Second empirical formula is between $Zn^{2+}(Positive ion) and O^{2-}(Negative ion)$

Second Formula would be $Zn_{2}O_{2}$

Note : When the subscript are same they get cancel out, so $Zn_{2}O_{2}$ would be written as $ZnO$

Third empirical formula is between $Ni^{4+}(Positive ion) and F^{-}(Negative ion)$

Third Formula would be : $NiF_{4}$

Forth empirical formula is between $Ni^{4+}(Positive ion)and O^{2-}(negative ion)$

Forth Formula would be : $Ni_{2}O_{4}$ or $NiO_{2}$

Note- The subscript will be simplified and the formula will be written as $NiO_{2}$ .

The empirical formula of four binary ionic compounds are : $ZnF_{2}, ZnO, NiF_{4},NiO_{2}$

8 0

3 years ago

Read 2 more answers

Calculate the internal energy (in Joules) of a system that loses 134.8 J that is compressed with a pressure of 5.73 atm from 8.5

Nataly_w [17]

The change in the internal energy of the system is -4511.8 J.

<h3>What is the change in the internal energy?</h3>

We know that according to the first law of thermodynamics, energy can neither be created nor destroyed but can be transformed from one form to the other.

Now we know that;

ΔE = q + w

ΔE = Change in internal energy

q = heat absorbed or evolved

w = work done

Now we have;

q = - 134.8 J (The system losses heat)

w = PdV

w = 5.73 (1.00 - 8.540)

w = -43.2 Latm or -4377 J

Then we have;

ΔE = - 134.8 J + (-4377 J)

ΔE = -4511.8 J

Learn more about internal energy:brainly.com/question/11278589

#SPJ1

5 0

2 years ago

Which of the following is the best definition of thermal energy?

Shtirlitz [24]

The answer is D. Because the other answers dont make any sense. - Dont have another account under bestfrienisbecky

6 0

4 years ago

Read 2 more answers

one side of a cube measures 0.53 cm. the mass of the cube is 0.92 g. what is the density of the cube

ziro4ka [17]

Answer:

6.17 g/cm³

Explanation:

Data given:

one side of cube = 0.53 cm

mass of the cube is 0.92 g

density of the cube = ?

Solution:

First we will calculate for volume the cube

As we know all the sides or edges of a cube are equal so volume equation will be

So,

V = length x width x height

V = e³

as on side = 0.53 cm

then

V = (0.53 cm)³

V = 0.149 cm³

Now we will calculate density of cube

To calculate density, formula will be used

d = m/v . . . . . (1)

where

d = density

m = mass

v = volume

put values in above formula 1

d = 0.92 g / 0.149 cm³

d = 6.17 g/cm³

so. the density of cube = 6.17 g/cm³

7 0

3 years ago